Answer:
Yes, he is meeting his original goal to be successful.
The critical value is 1.833
Step-by-step explanation:
H0: mu = 300
Ha: mu > 300
The test is a one-tailed test because the alternate hypothesis is expressed using greater than.
Test statistic (t) = (sample mean - population mean) ÷ (sample sd/√n)
sample mean = 335
population mean = 300
sample sd = 50
n = 2×5 = 10
t = (335 - 300) ÷ (50/√10) = 35 ÷ 15.81 = 2.21
Degree of freedom = n-1 = 10-1 = 9
Significance level = 5%
Critical value corresponding to 9 degrees of freedom and 5% significance level is 1.833.
Conclusion:
Reject the null hypothesis because the test statistic 2.21 is greater than the critical value 1.833.
His original goal to be successful is contained in the alternate hypothesis, therefore, he is meeting it.
Answer:
A) 23cm.
B) 32.0625 square cm.
Step-by-step explanation:
<u>Perimeter:</u> Just add all the sides together like so:
4.75x2 + 6.75x2 = 23cm.
<u>Area:</u> Multiply the base and height together:
4.75 x 6.75 = 32.0625 square cm.
Answer:
Least Common Multiple of 3 , 4 and 7 is 84 .
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
Let x be the number of students in the class
15 is 60% of x
60% of x can be written as 0.6x
15 = 0.6x
Divide by 0.6 on both sides
25 = x
There are 25 students in the class
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Answer:
(5, -2), or x = 5 and y = -2.
Step-by-step explanation:
We can solve the two equations algebraically by eliminating a variable:
2x + 5y = 0
3x - 4y = 23
Eliminate the x variable by finding the least common multiple and multiplying both equations:
3(2x + 5y = 0)
2(3x - 4y = 23)
Distribute and subtract the bottom equation from the top:
6x + 15y = 0
6x - 8y = 46
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0x + 23y = -46
23y = -46
y = -2.
Plug in y into an equation to solve for x:
2x + 5(-2) = 0
2x - 10 = 0
2x = 10
x = 5. Therefore:
The solution to this equation is (5, -2), or x = 5 and y = -2.