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3 years ago

Quadrilaterals are similar if their corresponding sides are proportional. true or false

Mathematics

2 answers:

Dafna11 [192]3 years ago

6 0

Answer:

FALSE

Step-by-step explanation:

Corresponding angles must also be congruent for the figures to be similar. Proportional sides is <em>not a sufficient condition</em>.

lara [203]3 years ago

5 0

Answer:

The given statement is true.

Step-by-step explanation:

Quadrilaterals are similar if their corresponding sides are proportional.

This statement is true.

Quadrilaterals are similar when

a) corresponding angles are equal

b) the corresponding sides are proportional i,e the ratios of corresponding sides are equal

So, the given statement is true.

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Which of the following is a reflection of ( 2,4 ) across the x-axis?

fiasKO [112]

Answer:

(2,-4)

Step-by-step explanation:

(2,4) is located in Quadrent I (+,+), if you reflect over the x-axis, it would be in Quadrent IV (+,-).

if you dont understand I suggest you draw a coordinate plane on a graphing notebook.

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3 years ago

Carolyn watched two movies with her brother. They watched the first movie from 1:38 p.m. to 2:55 p.m. and the second movie from

Olegator [25]

Answer:

They watched movies for 2 hours and 52 minutes.

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3 years ago

last year 1/5 of the students in your class played a sport this year 10 students join the class five of the new students play a

tino4ka555 [31]

Answer:

Step-by-step explanation:

last year 1/5 of the class played sports, so s = (1/5) c

the next year, s increased by 5, c increased by 10 and the fraction changed to 1/4, so for the next year (s+5) = (1/4)(c+10)

To solve this we can substitute s = (1/5)c from the first equation into the second, so

((1/5)c + 5)=(1/4)(c+10), simplify both sides

(1/5)c + 5 = (1/4)c + 10/4, simplify 10/4 to 5/2

(1/5)c + 5 = (1/4)c + 5/2, multiply both sides by 20 to eliminate fractions (least common multiple of 2, 4 and 5)

4c + 100 = 5c + 50, subtract 4c, subtract 50 from both sides

50 = c, number of students in class last year was 50, this year is 10 more, so this year is 60

5 0

3 years ago

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

5 0

3 years ago

Justine has 4 1/2 pounds of red apples, 3 1/4 pounds of green apples, and 2 1/4 pounds of yellow apples. How many kilograms of a

Darina [25.2K]

4 1/2 + 3 1/4 + 2 1/4 = 10 pounds of apples.

10 pounds is approximately 4.5 kilograms.

7 0

2 years ago