The hourly wage is approximately $26 per hour. Find out how many hours the person works per year by multiplying 40 x 50 to get 2,000 hours. Then divide 52,000 by 2,000 to get the person's hourly wage, which is $26 hours per hour.
<span>The tortoise is runing one mile per hour the entire race.
The hare is runing 3/4 only the first half.
If we multiply by 2 totis =2 miles and hare =1.50 the hare need to run 1/2 or .50 faster to beat the tortis.</span>
Answer:
0.11069
Step-by-step explanation:
We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.
P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =
I hope that works for you!
A relation is any set of ordered pairs, which can be thought of as (input, output).
A function is a relation in which NO two ordered pairs have the same first component and different second components.
The set of first components (x-coordinates) in the ordered pairs is the DOMAIN of the relation.
The set of second components (y-coordinates) is the RANGE of the relation.
Part 1:
Domain: {-1, 1, 3, 6}
Range: {2, 2, 2, 2}
Part 2:
To determine whether the given relation represents a function, look at the given relation and ask yourself, “Does every first element (or input) correspond with EXACTLY ONE second element (or output)?”
Remember that a function can only take on 1 output for each input.
It helps to plot the points on the graph and perform the Vertical Line Test (VLT):
The Vertical Line Test allows us to know whether or not a graph is actually a function. If a vertical line intersects the graph in all places at exactly one point, then the relation is a function.
As you can see in the attached screenshot, every vertical line drawn only has 1 point in it. This means that each x-value corresponds to exactly one y-value. The given relation passed the VLT. Therefore, the relation is a function.
Please mark my answers as the Brainliest if you find my explanation helpful :)
we are given
we can write it in terms of exponents
Firstly , we will simplify numerator
now, we can add exponents
we can cancel it
and we get
............Answer