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kozerog [31]
3 years ago
7

Without computing, determine which number is greater, [(-4)^4]^5 or -[(4^12)^3 Explain your reasoning.

Mathematics
1 answer:
Strike441 [17]3 years ago
7 0

Answer:

I think [(-4)^4]^5, but I'm not completely sure

Step-by-step explanation:

1.0995116e+12 greater than -4.7223665e+21

[(-4)^4]^5=1.0995116e+12

-[(4^12)^3=-4.7223665e+21

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What is the surface area of the cylinder in terms of pi? The diagram is not drawn to scale.
bearhunter [10]
Surface Area = 2πr² + 2πrh 

Surface Area = 2π(7)² + 2π(7)(15) = 308π in²²

Answer: 308π in²
3 0
3 years ago
How to write 12,375,003 in expanded form
icang [17]
Twelve million threehundred and seventy five thousand ans three
6 0
3 years ago
What is 125^2/3 in simplest form? and What is \sqrt[5]({-245} ) ^{5} in simplest form?
Natasha_Volkova [10]
{ 125 }^{ \frac { 2 }{ 3 }  }\\ \\ ={ \left( { 125 }^{ \frac { 1 }{ 3 }  } \right)  }^{ 2 }\\ \\ ={ \left( \sqrt [ 3 ]{ 125 }  \right)  }^{ 2 }\\ \\ ={ 5 }^{ 2 }\\ \\ =25

This is because:

{ a }^{ \frac { m }{ n }  }\\ \\ =\sqrt [ n ]{ { a }^{ m } }

Remember that:

5 x 5 x 5 = 125
5 0
3 years ago
Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the
s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

F(x)=\sqrt{x-2}

G(x)=(x-2)^2

H(x)=x^2+2

We compose F(x) and G(x) to get:

(F\circ G)(x)=F(G(x))

(F\circ G)(x)=F((x-2)^2)

(F\circ G)(x)=\sqrt{(x-2)^2-2}

(F\circ G)(x)=\sqrt{x^2-4x+4-2}

(F\circ G)(x)=\sqrt{x^2-4x+2}

(F\circ G)(x)\ne x

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

(F\circ H)(x)=F(H(x))

(F\circ H)(x)=F(x^2+2)

(F\circ H)(x)=\sqrt{x^2+2-2}

We simplify to get:

(F\circ H)(x)=\sqrt{x^2}

(F\circ H)(x)=x

Since (F\circ H)(x)=x, H(x) is an inverse of F(x)

3 0
3 years ago
Find out the cylinders volume whose height is 3 cm and radius 5cm
Studentka2010 [4]
Volume = πr²h

Volume = π(5)²(3)

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----------------------------------------------
Answer: Volume = 235.62 cm³.
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8 0
3 years ago
Read 2 more answers
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