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3 years ago

Simplify the expression 2(3x-y)+5(x+2y)

Mathematics

2 answers:

Levart [38]3 years ago

8 0

distribute

(6x-2y)+(5x+10y)

11x+8y

BaLLatris [955]3 years ago

7 0

2(3x - y) + 5(x + 2y)

6x - 2y + 5x + 10y

Simplify the expression

11x + -8y is your final answer

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Pencils come in packages of 10.Erasers come in packages of 12. Phillips wants to purpose the smallest number of pencils and eras

balandron [24]

Answer:

The answer to your question is:

Packages of pencils = 6

Packages of erasers = 5

Step-by-step explanation:

Data

Pencils = 10/package

Erasers = 12 / package

Process

Find the least common factor of 10 and 12

10 12 2

5 6 2

5 3 3

5 1 5

LCF = 2 x 2 x 3 x 5 = 60

Finally divide 60 by the number of pencils or erasers in each package

Packages of pencils = 60/10 = 6

Packages of erasers = 60/12 = 5

5 0

3 years ago

Stephen evaluated (6.34 times 10 Superscript negative 7 Baseline) (4.5 times 10 Superscript 3 Baseline). His work is shown below

Maksim231197 [3]

Answer:

The step 4 and 5 describe the errors Stephen made.

Step-by-step explanation:

Given : Stephen evaluated $(6.34\times 10^{-7})(4.5\times 10^3)$ . His work is shown below.

To find : Which two statements describe the errors Stephen made?

Solution :

Step 1 - $(6.34\times 10^{-7})(4.5\times 10^3)$

Step 2 - $(6.34\times 4.5)(10^{-7}\times 10^3)$

Step 3 - $(28.53)(10^{-4})$

Step 4 - $28.53\times 10^{4}$

Error is the step as 4 sign is negative.

So correct step is $28.53\times 10^{-4}$

Step 5 - $28.53\times 10^{3}$

Error is the step as there is 4 in place of 3.

So correct step is $28.53\times 10^{-4}$

The step 4 and 5 describe the errors Stephen made.

7 0

3 years ago

Read 2 more answers

Find the domain and range of the function graphed in the picture.

algol [13]

The domain is the set of allowed x inputs, or x coordinates of a function. In this case, any point on the curve has an x coordinate that is 4 or smaller.

Therefore, the domain is the set of numbers x such that $x \le 4$

To write this in interval notation, we would write $(-\infty, 4]$ This interval starts at negative infinity and stops at 4. We exclude infinity with the curved parenthesis and include 4 with the square bracket.