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Luba_88 [7]
3 years ago
15

4(x + 1) − 7x = −3 (x − 1) + 1

Mathematics
1 answer:
grigory [225]3 years ago
7 0
The apartment complex has 20 apartment per buildings 4 apartment are 3 bedroom apartment, 7 are 2 bedroom unit,and 9 apartment are 1 bedroom units.if the apartment complex builds 50 buildings how many 3 bedroom units would they have?
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When 4(0.5x+2.5y-0.7x-1.3y+4)is simplified, what is the resulting expression?
Wittaler [7]
2x+10y-2.8x-5.2y+16=

-0.8x+4.8y+16

3 0
3 years ago
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Kate has an interior decorating business. She charges a base fee of $25 for each visit and $40 per hour for her labor. 1) Write
nataly862011 [7]

Answer:

1) C = $25 + $40 × h

2) The domain for the ≠unction is 0 ≤ h ≤ ∞

The range for the function is 25 ≤ C ≤ ∞

3) Continuous

Step-by-step explanation:

1) The given parameters are;

The base fee charged = $25

The amount charged for labor = $40/hour

The total cost for h number of hours is C = $25 + $40 × h

2) The domain for the ≠unction is 0 ≤ h ≤ ∞

The range for the function is 25 ≤ C ≤ ∞

3) The situation is continuous because the different input values of h can be infinite (from o to infinity)

3 0
2 years ago
Which equation best matches the scenario below?
siniylev [52]

Answer:

Definetly t = 4n

4 0
2 years ago
Which polynomial correctly combines the like terms and puts the given polynomial in standard form? -5x^3y^3+8x^4y^2-xy^5-2x^2y^4
victus00 [196]

Given:

The polynomial is:

-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5

To find:

The simplified form of the given polynomial in standard form.

Solution:

We have,

-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5

Combining the like terms, we get

=-5x^3y^3+8x^4y^2+(-2x^2y^4+3x^2y^4)+8x^6+(-xy^5-6xy^5)

=-5x^3y^3+8x^4y^2+x^2y^4+8x^6-7xy^5

Now, rewrite this polynomial in standard form.

=8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5

Therefore, the required polynomial in standard form is 8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5.

8 0
2 years ago
Helpppp!!!! Plzzzzzzzzz
dmitriy555 [2]

Answer:

false

Step-by-step explanation:

5 0
2 years ago
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