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Oksanka [162]
3 years ago
11

Select other ways to express 10^{4}

{4} " align="absmiddle" class="latex-formula"> Mark all that apply.
A: 10x4
B: 10+4
C: 1,000
D: 10,000
E: 10+10+10+10
F: 10x10x10x10³
Mathematics
2 answers:
Sedbober [7]3 years ago
4 0
I think it might be D and F maybe
dangina [55]3 years ago
3 0
F because it just is<span />
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What is the distance between P(12, 4) and Q(-8, 2)
abruzzese [7]

\huge{\boxed{2 \sqrt{101}}}

The distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, where (x_1, y_1) and (x_2, y_2) are the points.

Substitute in the points. \sqrt{(2-4)^2+(-8-12)^2}

Subtract. \sqrt{(-2)^2+(-20)^2}

Solve the exponents. \sqrt{4+400}

Add. \sqrt{404}

Now, we can simplify this square root just a little bit. 404 has a square factor of 4. \sqrt{404}=\sqrt{4}*\sqrt{101}

The square root of 4 equals 2. \boxed{2 \sqrt{101}}

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3 years ago
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What is the simplified value of the expression below?<br><br> 12.4 x (negative 6.3)
MrRa [10]

Answer:

78.12

Step-by-step explanation:

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We have n = 100 many random variables Xi ’s, where the Xi ’s are independent and identically distributed Bernoulli random variab
777dan777 [17]

Answer:

(a) The distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

(c) The value of P(\bar X>0.50) is 0.50.

Step-by-step explanation:

It is provided that random variables X_{i} are independent and identically distributed Bernoulli random variables with <em>p</em> = 0.50.

The random sample selected is of size, <em>n</em> = 100.

(a)

Theorem:

Let X_{1},\ X_{2},\ X_{3},...\ X_{n} be independent Bernoulli random variables, each with parameter <em>p</em>, then the sum of of thee random variables, X=X_{1}+X_{2}+X_{3}...+X_{n} is a Binomial random variable with parameter <em>n</em> and <em>p</em>.

Thus, the distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

The sample size is large, i.e. <em>n</em> = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu=p=0.50

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05

(c)

Compute the value of P(\bar X>0.50) as follows:

P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\

                    =P(Z>0)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the value of P(\bar X>0.50) is 0.50.

8 0
3 years ago
A spinner marked A, B, C is spun then a 6-sided die is rolled. What is the probability of getting a B and then a 6.
BigorU [14]

Given:

A spinner marked A, B, C is spun then a 6-sided die is rolled.

To find:

The probability of getting a B and then a 6.

Solution:

We know that,

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Total possible values for a spinner are 3. So, the probability of getting B, we get

P(B)=\dfrac{1}{3}

Total possible values for a die are 6. So, the probability of getting 6, we get

P(6)=\dfrac{1}{6}

Now, the probability of getting a B and then a 6 is

P(B,6)=\dfrac{1}{3}\times \dfrac{1}{6}

P(B,6)=\dfrac{1}{18}

The required probability is \dfrac{1}{18}.

Therefore, the correct option is D.

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Which part of the water cycle is responsible for cloud formation ​
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It’s Condensation !!


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