X^2(x+2)-4(x+2)
(x^2-4) (x+2) = 0
do you have to keep going/?
or thats all they want?
Answer:
y=-1.5x-4
Step-by-step explanation:
Slope intercept form is y=mx+b
Bring x over to the other side
2y=-8-3x
divide by 2
y=-4-1.5x
y=-1.5x-4 should be your equation in slope-intercept form
Answer:
(f+g)(2) = 4
(f-g)(4) = 8
(f ÷g)(2) = 7
(f x g)(1) = 0
Step-by-step explanation:
We are given these following functions:
(f+g)(2)
At 
Then
(f+g)(2) = 4
(f-g)(4)
At x = 4
Then
(f-g)(4) = 8
(f ÷g)(2)
At x = 2
Then
(f ÷g)(2) = 7
(f x g)(1)
Then
So
(f x g)(1) = 0
Which relation is a function? Question 3 options: {(1, 2); (1, 3); (1, 4); (1, 5)} {(1, 2); (2, 3); (3, 4); (4, 5)} {(1, 2); (3,
NeTakaya
To be a function for every identical x value it has to have a different Y value. If the set has two identical X values but they have different Y values it can't be a function.
The set that is a function is:
{(1, 2); (2, 3); (3, 4); (4, 5)}
Answer:
Step-by-step explanation:
um
