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3 years ago

Solve the equation, 4 - (x + 1) = 6. x = -9 x = 3 x = -3 x = 9

Mathematics

1 answer:

sertanlavr [38]3 years ago

5 0

Answer:

x = -3

Step-by-step explanation:

$4-(x+1) =6$

Distribute the negative

$4 - x - 1 = 6$

Combine like terms on Left Hand Side

$- x + 3 = 6$

Substract 3 from both sides

$-x = 3$

Divide both sides by -1 to get rid of the negative

∴ $x = - 3$

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Summer campers were surveyed about their favorite fruit. The resulting table shows the data collected from the survey. Use the i

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Answer:

Step-by-step explanation: 90

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3 years ago

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The area of a rectanglular sandbox is (5x + 40) feet. Factor 5x + 40 to find possible dimensions of the sandbox

kotegsom [21]

5x+40 factors to 5(x+8). Notice how distributing the 5 back through to each term in the parenthesis gives
5 times x = 5x
5 times 8 = 40
So 5*(x+8) = 5*x+5*8 = 5x+40

Therefore, the factors are 5 and (x+8).
The dimensions of the sandbox are 5 feet by (x+8) feet.

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3 years ago

Angle A= ? <br> HELP HELP HELP

vazorg [7]

Answer:

A = 41.41

Step-by-step explanation:

Since this is a right angle, we can use trig functions

cos A = adjacent/ hypotenuse

Cos A = 6/8

Taking the inverse cos of each side

cos ^ -1 ( cos A) = cos ^-1 ( 6/8)

A =41.40962211

Rounding to the nearest hundredth

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3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

$P(x \ge 60) \approx P(z > 1.34)$