I need help with 3-4 quick

In the regular octagon, the numeric value of the area of the shaded region is twice more than the numeric value of the length of

s2008m [1.1K]

Answer:

A = (2+√8)L² - 2L, where L is the length of AB

Step-by-step explanation:

Lets call L the length of one side. The octagon can be divided in 8 triangles composed by the vertices of the octagon and the center. The base of each triangle has length L and the height is L/2 + M, with M such that 2M² = L². This is because the center of the octagon is located at middle height of the center sides. You can reach that height by 'travelling' from the bottom side throught one slanted side (which is the hypotenuse of a isosceles rectangle triangle of height M) and then you travel throught a center side half its length. Thus, h = L/2 + L/√2.

The area of each triangle of the octagon therefore is, as a result, h*L/2 = L²/4 + L²/2√2

Hence, the area of the octagon is 8*(L²/4 + L²/2√2) = (2+√8)L². The unshaded region area can be computed by taking this number and substract to it the value of 2L, which is the area of the shaded region (The double of the length of a side)

As a result,

A = (2+√8)L² - 2L

8 0

3 years ago

I'd appreciate it if anyone could help ASAP! :) I'll give Brainliest!

sergiy2304 [10]

We have been given a graph of function g(x) which is a transformation of the function $f(x)=3^x$

Now we have to find the equation of g(x)

Usually transformation involves shifting or stretching so we can use the graph to identify the transformation.

First you should check the graph of $f(x)=3^x$

You will notice that it is always above x-axis (equation is x=0). Because x-axis acts as horizontal asymptote.

Now the given graph has asymptote at x=-2

which is just 2 unit down from the original asymptote x=0

so that means we need shift f(x), 2 unit down hence we get:

$y=3^x$

but that will disturb the y-intercept (0,1)

if we multiply $3^x$ by 3 again then the y-intercept will remain (0,1)

Hence final equation for g(x) will be:

$g(x)=3(3^x)-2$

5 0

3 years ago

Sam is hired for a 20-day period. On days that he works, he earns $60. For each day that he does not work, $30 is subtracted fro

Alenkinab [10]

Answer:

He did not work for 6 days

Step-by-step explanation:

Sam is hired for a 20-day period.

Let x be the no. of days he did not work

So, No. of days he worked = 20-x

he earns per working day = $60

So, he earns for (20-x) days = 60(20-x)

For each day that he does not work, $30 is subtracted from his earnings.

So, Amount deducted for x days = 30x

So, His earning for 20 days = $60(20-x)-30x$

We are given that At the end of the 20-day period, he received $660

So, $60(20-x)-30x=660$

$1200-60x-30x=660$

$1200-90x=660$

$1200-660=90x$

$540=90x$

$\frac{540}{90}=x$

$6=x$

So, he did not work for 6 days

So, Option C is true

5 0

3 years ago

At what point do 3x-2=26 and 5x=7y+58 intersect?

shutvik [7]

$3x-2=26\qquad\text{add 2 to both sides}\\\\3x=28\qquad\text{divide both sides by 3}\\\\\boxed{x=\dfrac{28}{3}}\\\\\text{Put the value of x to the second equation}\ 5x=7y+58\\\\5\left(\dfrac{28}{3}\right)=7y+58\qquad\text{multiply both sides by 3}\\\\(5)(28)=21y+174\\\\140=21y+174\qquad\text{subtract 174 from both sides}\\\\-34=21y\qquad\text{divide both sides by 21}\\\\\boxed{y=-\dfrac{34}{21}}\\\\Answer:\ \boxed{\left(\dfrac{28}{3},\ -\dfrac{34}{21}\right)}$

7 0

3 years ago

Write the equivalent mixed number: 50/7

Wewaii [24]

I'm pretty sure it's 7 and 1/7

7 0

3 years ago