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VladimirAG [237]
2 years ago
13

The figure shows a construction completed by hand.

Mathematics
1 answer:
Tresset [83]2 years ago
7 0

Based on the construction, we can logically deduce that: A. yes; the compass was kept at the same width to create the arcs for points C and D.

<h3>What is a line segment?</h3>

A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.

In Geometry, a line segment can be measured by using the following measuring instruments:

  • A scale (ruler)
  • A divider
  • A compass

<h3>What is an arc?</h3>

In Geometry, an arc can be defined as a trajectory that is generally formed when the distance from a given point has a fixed numerical value.

Based on the construction with arcs created above and below the line segment from points A, we can infer and logically deduce that it is true that the compass was kept at the same width to create the arcs for points C and D.

In conclusion, yes, the construction demonstrated how to bisect a line segment correctly by hand.

Read more on arcs here: brainly.com/question/11126174

#SPJ1

Complete Question:

The construction has a given segment AB. Arcs have been created above and below the segment from points A that are equidistant from point A. The compass was kept at the same distance, placed on point B, and two additional arcs were created above and below the segment that intersect with the first arcs created. The intersection of the arcs above the segment created point C. The intersection of the arcs below the segment created point D. A line was drawn from point C to D through the segment.

Does the construction demonstrate how to bisect a segment correctly by hand?

A. Yes; the compass was kept at the same width to create the arcs for points C and D.

B. Yes; a straightedge was used to create segment CD.

C. No; the compass was not kept at the same width to create the arcs for points C and D.

D. No; a straightedge was used to create segment CD.

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For how many three digit numbers (100 to 999) is the sum of the digits even? (For example, 343 has an even sum of digits: 3 + 4
n200080 [17]

Answer:

there are 425 numbers of three digits whose the sum of the digits is even.

Step-by-step explanation:

Option 1:

It is necessary to accomplish one of the next conditions:

(1) all of the digits are even.

(2) exactly 2 of the digits are odd

Then, for the first condition:

4x5x5 = 100 -> this is because the first digit can not be 0.

for the second condition:

(3C1)*5*5*5-1*5*5 =3*125-25=350

where 3C1 is a combination.  The 3C1 determines which of the three digits is even, and it is necessary to subtract the numbers under 100 with the other 2 digits odd.

So, there are 450 numbers of three digits whose the sum of the digits is even.

Option 2:

there are 900 three digit number and 5*5*5 =125 has 3 odd numbers and 5*5*5+4*5*5+4*5*5=325 has 1 odd number, so there are 450 numbers of three digits whose the sum of the digitis is odd, so 900-450 whose the sum of the digits is even.

4 0
3 years ago
1. How many more monthly payments are made for a five-year loan than for a three-year loan?​
Gemiola [76]

Answer: There are 24 more payments made.

Step-by-step explanation:

In a 5 year loan there is 60 months

In a 3 year loan there is 36 months.

7 0
2 years ago
Select the graph for the solution of the open sentence. Click until the correct graph appears. 2|x| + 1 &lt; 5
Vedmedyk [2.9K]

Answer:

1st Answer

Step-by-step explanation:

6 0
3 years ago
Twenty five heat lamps are connected in a greenhouse so, that when one lamp fails, another takes over immediately (only one lamp
olga55 [171]

Answer:

P = 0.006

Step-by-step explanation:

Given

n = 25 Lamps

each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours

Find probability that the lamp will be burning at end of 1300 hours period.

As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have

Suppose i represents lamps

P (∑i from 1 to 25 (X_i > 1300)) = 1300

= P(X^{'}> \frac{1300}{25})                  where X^{'} represents mean time of a single lamp

= P (Z> \frac{52-50}{\frac{1}{\sqrt{25}}})                Z is the standard normal distribution which can be found by using the formula

Z = Mean Time (X^{'}) - Life time of each Lamp (50 hours)/ (SD/\sqrt{n})

Z = (52-50)/(4/\sqrt{25}) = 2.5

Now, P(Z>2.5) = 0.006 using the standard normal distribution table

Probability that a lamp will be burning at the end of 1300 hours period is 0.006

4 0
3 years ago
!Help Help Help! lols
Gwar [14]

the Answer is c. I think

6 0
3 years ago
Read 2 more answers
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