Question

My teacher wanted us to try this out, but I don't understand it as much.

Answer 1

solve for the indicated variable means isolate that variable.

Ans(7)

P=IRT (T)

that means solve for T or make T alone on one side of equal.

To do that we just need to move IR on the left side

So we get:

$\frac{P}{IR}=T$

Hence final answer will be $T=\frac{P}{IR}$

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Ans(8)

2x-3y=8  (y)

-3y=8-2x

$y=\frac{8-2x}{-3}$

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Ans(9)

V=LWH  (L)

$L=\frac{V}{WH}$

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Ans(10)

A=2(L+W)  (w)

A=2L+2W

A-2L=2W

$\frac{A-2L}{2}=W$

$W=\frac{A-2L}{2}$

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Ans(11)

ax+by=c  (y)

by=c-ax

$y=\frac{c-ax}{b}$

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Ans(12)

$P=\frac{R-C}{N}$ (R)

PN=R-C

PN+C=R

R=PN+C