All categories

2 years ago

Can someone please tell me how to do this?

Mathematics

2 answers:

max2010maxim [7]2 years ago

5 0

X=16 because 16 x 2=32 and both sides look pretty equal so.

ziro4ka [17]2 years ago

3 0

The vertical angles are congruent (or equal) so,

32 = 2x

2x = 32

2x/2 = 32/2 ..... dividing both sides by 2

x = 16 which is the answer

You might be interested in

How would the number be written in standard form? 30,000+500+70+6

Lisa [10]

30,576 because 30 fills the thousands and 5,7,6 fill the rest

4 0

2 years ago

Read 2 more answers

Through: (-5, -3), perp. to y=-9/4x-5

Mrrafil [7]

Given:

A line passes through (-5,-3) and perpendicular to $y=-\dfrac{9}{4}x-5$ .

To find:

The equation of the line.

Solution:

We have,

$y=-\dfrac{9}{4}x-5$

On comparing this equation with slope intercept form, i.e., $y=mx+b$ , we get

$m_2=-\dfrac{9}{4}$

It means, slope of this line is $-\dfrac{9}{4}$ .

Product of slopes of two perpendicular lines is always -1.

$m_1\times m_2=-1$

$m_1 \times \left(-\dfrac{9}{4}\right)=-1$

$m_1=\dfrac{4}{9}$

Slope of required line is $\dfrac{4}{9}$ and it passes through the point (-5,-3). So, the equation of the line is

$y-y_1=m(x-x_1)$

where, m is slope.

$y-(-3)=\dfrac{4}{9}(x-(-5))$

$y+3=\dfrac{4}{9}(x+5)$

$9(y+3)=4(x+5)$

$9y+27=4x+20$

$27-20=4x-9y$

$7=4x-9y$

Therefore, the equation of required line is $4x-9y=7$ .

8 0

2 years ago

Barry is trying to calculate the distance between point E(3, 1) and point F(4, 7). Which of the following expressions will he us

maxonik [38]

D=√((7-1)^2+(4-3)^2)=√37

6 0

2 years ago

Read 2 more answers

What is zero of the polynomial and example

stich3 [128]

<span> Binomials and trinomials are two types of polynomials. The first has two terms and the second has three.</span>

8 0

3 years ago

The length of a rectangle is 1 less than twice the width.

vladimir1956 [14]

$w-width\\2w-1-length\\w(2w-1)=2w^2-w-the\ area\\28\ ft^2-the\ area\\\\\text{The equation:}\\\\2w^2-w=28\qquad\text{subtract 28 from both sides}\\\\2w^2-w-28=0\\\\2w^2-8w+7w-28=0\\\\2w(w-4)+7(w-4)=0\\\\(w-4)(2w+7)=0\iff w-4=0\ \vee\ 2w+7=0\\\\w-4=0\qquad\text{add 4 to both sides}\\\boxed{w=4}\\\\2w+7=0\qquad\text{subtract 7 from both sides}\\2w=-7\qquad\text{divide both sides by 2}\\w=-3.5$

7 0

2 years ago

Read 2 more answers