Answer:
14
Step-by-step explanation:
add the stuff together
Answer:
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Step-by-step explanation:
Total plants = 11
Domestic plants = 7
Outside the US plants = 4
Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:
P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ
where n = total no. of trials
x = no. of successful trials
p = probability of success
q = probability of failure
Here we have n=4, p=4/11 and q=7/11
P(X≥1) = 1 - P(X<1)
= 1 - P(X=0)
= 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰
= 1 - 0.16399
P(X≥1) = 0.836
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
5 liters (L) of 30% bleach solution contains 0.3×(5 L) = 1.5 L of bleach.
3 L of 50% bleach contains 0.5×(3 L) = 1.5 L of bleach, too.
Combined, you would have 8 L of solution containing 1.5 L + 1.5 L = 3 L of bleach, so the concentration of bleach is
(3 L) / (8 L) = 0.375 = 37.5%
Answer:
983040
Step-by-step explanation:
Second Year : 15x4=60
Third Year : 60x4=240
Fourth Year : 240x4=960
Fifth Year : 960x4=3840
Sixth Year : 3840x4=15360
Seventh Year : 15360x4 = 61440
Eighth Year: 61440x4=245760
Ninth Year : 245760x4= 983040
Answer:
y+9=3/4(x-8)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-9)=3/4(x-8)
y+9=3/4(x-8)
