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Bezzdna [24]
3 years ago
14

For a biology project, you measure the weight in grams and the tail length in millimeters of a group of mice. The correlation is

r = 0.9. If you had measured tail length in centimeters instead of millimeters, what would be the correlation? (There are 10 millimeters in a centimeter.)
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that for a biology project, you measure the weight in grams and the tail length in millimeters of a group of mice.

The correlation is r = 0.9

If you had measured tail length in centimeters instead of millimeters, what would be the correlation?

For this we must understand the meaning of correlation and formula

Correlation is a measure of linear association between the two variables and always lie between -1 and 1

This is got by dividing covariance of (x,y) by product of std deviation of x and y

So because we changed the units of length correlation coefficient would not change.

It would remain the same as 0.90

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Can someone please calculate the length ?
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<h3>Answer:  11/20</h3>

=====================================================

Work Shown:

x = unknown horizontal length

1/5 = 0.2

Perimeter = 2*(width + length)

P = 2*(0.2 + x)

P = 0.4 + 2x

Set this equal to the given perimeter of 1 & 1/2 = 1.5 and solve for x

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x = 55/100

x = (5*11)/(5*20)

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3 years ago
A set of numbers satisfies Benford’s Law if the probability of a number starting with digit d is P(d) = log(d + 1) – log(d).
irakobra [83]

Interpreting the graph and the situation, it is found that the values of d that can be included in the solution set are 1 and 4.

----------------------

  • According to Benford's law, the probability of a number starting with digit is d is:

P(d) = \log{(d + 1}} - \log{d}

  • A number can start with 10 possible digits, ranging from 1 to 9, which are all integer digits.
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A similar problem is given at brainly.com/question/16764162

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Simplify 6m2n3 – 3m3n2 + 8m2n3 + 12m3n2
NISA [10]
Hello! Hope I can assist you.

Let us simplify some terms first!

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From here, group like terms
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