Answer:
Carlos and Pamela drove 120 miles on the first day, 240 miles on the second day, and 290 miles on the third day.
Step-by-step explanation:
Let x be the number of miles driven on the first day.
Then they drove twice as many miles, or 2x on the second day
and 50 miles more than the second day's, so 2x + 50
The total is 650 across all three days, so we'll take the sum.
x + 2x + (2x + 50) = 650
Combine like terms on the left
5x + 50 = 650
Subtract 50 on both sides
5x = 600
Divide by 5 on both sides
x = 120
Check work:
120 + 2(120) + 2(120) + 50 = 650
120 + 240 + 240 + 50 = 650
600 + 50 = 650
650 = 650
So they drove 120 miles on the first day
2*120 = 240 miles on the second day
and 2*120 + 50 = 240 + 50 = 290 miles on the third day
Answer:
Choice C.
Step-by-step explanation:
A parallelogram is a quadrilateral with two pairs of opposite parallel sides.
There is a theorem that states that opposite sides of a parallelogram are congruent.
In this case, sides AB and CD are opposite sides.
Sides BC and AD are opposite sides.
Side CD is opposite side AB, so they are congruent.
Answer:
Choice C.
CD = AB; Opposite sides of parallelograms are congruent.
Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so
Answer:
can you zoom in on it
Step-by-step explanation:
Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
