Answer:Maybe that is inaropriate
Explanation:
Try rephrasing that
Value or power of a network grows exponentially as a function of the number of network members. this is known as Metcalfe's law. According to this law <span>the value (the power) of a </span>telecommunications network<span> is </span>proportional to the square of the number of connected users of the system (network members). Metcalfe's Law <span>characterizes many of the </span>network effects<span> of communication technologies and networks such as the </span>Internet<span>, </span>social networking<span> and the </span>World Wide Web<span>.</span>
Answer and Explanation
There are five stages of group development which Alex should follow.
i) Stage 1: Forming-this is where he forms a team which will follow the other stages.
ii)Stage 2: Storming - In this stage is where the members set their goals and boundaries.
iii)Stage 3: Norming- This is where the team comes together in terms of ideas. In this stage members are ready to move forward with big expectations.
iv)Stage 4: Performing.-This is where now the team is now accomplishing or implements their ideas and they are now getting the benefits.In this stage members argue positively.
v)Stage 5: Adjourning-This is the stage where the group has accomplished their mission.And now the group is dissolved
Answer:
Explanation:
The following is written in Java. It creates the function that takes in two int values to calculate the gcd. It includes step by step comments and prints the gcd value to the console.
public static void calculateGCD(int x, int y) {
//x and y are the numbers to find the GCF which is needed first
x = 12;
y = 8;
int gcd = 1;
//loop through from 1 to the smallest of both numbers
for(int i = 1; i <= x && i <= y; i++)
{
//returns true if both conditions are satisfied
if(x%i==0 && y%i==0)
//once we have both values as true we store i as the greatest common denominator
gcd = i;
}
//prints the gcd
System.out.printf("GCD of " + x + " and " + y + " is: " + gcd);
}
Let assume are lettered A to E in that order. Thus, there
will be 10 potential lines: AB, AC, AD, AE, BC, BD, BE, CD, CE and DE. Each of
these potential lines has 4 possibilities. Therefore, the total number of
topologies is 4¹⁰=1,048,576. 1,048,576. At 100ms <span>it will take 104,857.6 seconds which is slightly above 29 hours to inspect
each and one of them.</span>
