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3 years ago

A TCP ________ segment is a request to the other transport process to close a connection. ACK FIN SYN CLS

Computers and Technology

1 answer:

Greeley [361]3 years ago

4 0

Answer:

FIN

Explanation:

A TCP is an acronym for Transmission Control Protocol and it is one of the essential and important protocol of the internet protocol network. This simply means that, it is an essential part of the TCP/IP network.

The TCP has a wide range of applications in the following areas, file transfers, world wide web, remote administration, e-mail, etc.

The TCP connection are mainly established in the network using the three-way handshake.

A TCP FIN segment is a request to the other transport process to close a connection. The FIN in transmission control protocol (TCP) is an acronym for finish and it involves the packets associated with termination or closing of a network connection.

Generally, the TCP in networking is made up of all of the following flag bits, namely;

1. SYN: used for synchronizing packets associated with a connection.

2. ACK: this is mainly where an acknowledgement of packets in a network takes place.

3. FIN: it is used for closing connections.

4. PSH: used for pushing packets that are to meant to be delivered at the far end.

5. RST: used as a reset in times of errors in the connection.

6. URG: used to denote urgent and high priority packets in the network.

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3 years ago

Read 2 more answers

Assume values 10, 20, 30, and 40 are entered in the cell range A1:A4. Cell A10 contains the formula: =A1+A2+A3+A4 and displays v

r-ruslan [8.4K]

Answer:

The formula and value to this question is "=A1+A3+A4+A5 with value 100"

Explanation:

The explanation of the given question as follows:

In question, it is defined that four cells that are "A1, A2, A3, and A4" contains value that are "10, 20, 30, and 40".
To add these values we use addition formula that is "=A1+A2+A3+A4". it will give value 100.
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3 years ago

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alexira [117]

Answer:

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Explanation:

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3 years ago

Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r

kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

INVOKE Str_find,ADDR target, ADDR source

mov position,eax

jz wasfound ; ZF=1 indicates string found

mov edx,OFFSET str3 ; string not found

call WriteString

jmp quit

wasfound: ; display message

mov edx,OFFSET str1

call WriteString

mov eax,position ; write position value

call WriteDec

mov edx,OFFSET str2

call WriteString

quit:

exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

; to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

INVOKE Str_length,pTarget ; get length of target

mov lenTarget,eax

INVOKE Str_length,pSource ; get length of source

mov lenSource,eax

mov edi,OFFSET target ; point to target

mov esi,OFFSET source ; point to source

; Compute place in target to stop search

mov eax,edi ; stop = (offset target)

add eax,lenTarget ; + (length of target)

sub eax,lenSource ; - (length of source)

inc eax ; + 1

mov stop,eax ; save the stopping position

; Compare source string to current target

cld

mov ecx,lenSource ; length of source string

L1:

pushad

repe cmpsb ; compare all bytes

popad

je found ; if found, exit now

inc edi ; move to next target position

cmp edi,stop ; has EDI reached stop position?

jae notfound ; yes: exit

jmp L1 ; not: continue loop

notfound: ; string not found

or eax,1 ; ZF=0 indicates failure

jmp done

found: ; string found

mov eax,edi ; compute position in target of find

sub eax,pTarget

cmp eax,eax ; ZF=1 indicates success

done:

ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0

3 years ago