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notka56 [123]
3 years ago
10

Consider the right triangle. A right triangles with side lengths 28 meters and 45 meters. The hypotenuse is unknown. What is the

length of the hypotenuse StartRoot 53 EndRoot StartRoot 1,241 EndRoot 53 m 2809 m

Mathematics
2 answers:
omeli [17]3 years ago
8 0

Answer:

The answer is 53 or Square Root (sqrt) of 2809

Step-by-step explanation:

a^2+b^2=c^2

28^2+45^2=c^2

784+2025=c^2

c^2=sqrt 2809

c = 53

Mademuasel [1]3 years ago
6 0

Answer:

c

Step-by-step explanation:

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AnnyKZ [126]
Its 70 because it is
7 0
2 years ago
1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
3 years ago
A 8-foot tall man is standing beside a 32-foot flagpole. The flagpole is
kipiarov [429]

Answer:

The flagpole's shadow is 16.875 feet longer than the man's shadow

Step-by-step explanation:

The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;

Height of the shadow=actual height of the flagpole×factor

where;

length of the flagpole's shadow=22.5 feet

actual height of the flagpole=32 feet

factor=f

replacing;

22.5=32×f

32 f=22.5

f=22.5/32

f=0.703125

Using this factor in the expression below;

Length of man's shadow=actual height of man×factor

where;

length of man's shadow=m

actual height of man=8 feet

factor=0.703125

replacing;

length of man's shadow=8×0.703125=5.625 feet

Determine how much longer the flagpole's shadow is as follows;

flagpoles shadow-man's shadow=22.5-5.625=16.875 feet

The flagpole's shadow is 16.875 feet longer than the man's shadow

7 0
3 years ago
1. How many fourteenths are in 5/14?
never [62]

....... argue 6e73t83hwp260wcsihwoec

6 0
2 years ago
PLEASE HELP!! Trevor is writing a paper that must be 50,000 words long. He had already written 23,210 words. Write an inequality
almond37 [142]

Answer:

50,000 ≤ 23,210 + 5x

x = Average number of words per week

Step-by-step explanation:

Start off with 50,000 because that's how many words the paper needs to have.

Use "≤" because Trevor needs to write at least 50,000 words. (He can write more).

Trevor already wrote 23,210 words plus x words per week for 5 weeks.

(Solving for x will help you find the average number of words Trevor must write per week for 5 weeks).

5 0
3 years ago
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