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disa [49]
4 years ago
11

Given f(x)=3x2+4x and g(x)=2x2−x+1 .

Mathematics
2 answers:
RoseWind [281]4 years ago
4 0
3z^2 + 4x + 2x^2 - x + 1

5x^2 + 3x + 1: the answer is c
san4es73 [151]4 years ago
4 0
<h2>Answer:</h2>

Hence, the value of (f+g)(x) is:

                 5x^2+3x+1

<h2>Step-by-step explanation:</h2>

We are given a function f(x) in terms of variable x as:

f(x)=3x^2+4x

and function g(x) in terms of variable x as:

g(x)=2x^2-x+1

Now we are asked to find the value of (f+g)(x)

We know that:

(f+g)(x)=f(x)+g(x)

Hence, on putting the value of both the functions:

(f+g)(x)=3x^2+4x+2x^2-x+1

on combining like terms we get:

(f+g)(x)=3x^2+2x^2+4x-x+1

(f+g)(x)=5x^2+3x+1

                  The answer is:

                       5x^2+3x+1

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3 years ago
How o I get the awnser to 9s+3=57 I need help asap im in 8th grade
PIT_PIT [208]
First subtract 3 from both sides of the equal sign. 
9s + 3 = 57
      - 3     -3
9s = 54

Then divide both sides by 9.
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s = 6

You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6  + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)

Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations. 
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