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2 years ago

The largest moth is the Atlas moth. The Atlas moth is

Mathematics

1 answer:

Misha Larkins [42]2 years ago

5 0

11.8 to a mixed number is 11 8/10 or 11 4/5.

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(it says 8.5 at the left edge of orange) Find the total area of the prisms

tiny-mole [99]

Answer:

273.295 m^3

Step-by-step explanation:

Well I'm going to assume your talking about the volume first. :> So, let's find the orange one first cuz yes.

The rectangular prism has the volume of 8.5 x 5.7 x 4.3 and I think you should just use a calculator but I'll just tell you that the volume of this one is 208.335

Now we need to find the volume of the triangular prism which has side lengths of 3.5 6.4 and 5.8 . Now we must remember the strategy for finding the volume of a triangular prism is different because the formula is
V =(1/2)× b × h × l so lets plug in our values. Well, first 3.5 x 6.4 x 5.8 is 129.92 and then we multiply that by 1/2 and I'll tell you that it's 64.96

Finally, let us add the two values to find the total area. 208.335 + 64.96 is... 273.295 now remember the units it meters cubed!

7 0

1 year ago

If three X equal to 216 then find the value of 3 X - 2

lesya [120]

3X-2

=216-2

= 214

214 is the answer...

7 0

3 years ago

In a study of 200 students under 25

vlada-n [284]

Answer:

10%

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

2 years ago

In the right triangle shown in the diagram below,

adelina 88 [10]

QUESTION :-

what is the value of x to the nearest whole number?

ANSWER :-

$\cos( \theta) = \frac{base}{hypotenuse} \\ \cos(30) = \frac{x}{24} \\ \frac{ \sqrt{3} }{ \cancel2} = \frac{x}{ \cancel{24}} = \frac{x}{12} \\ 1.732 = \frac{x}{12} \\ 12 \times 1.732 = x \\ x = 20.7$

the nearest whole number-->

20.7 --> approximately --> 21 units

5 0

2 years ago