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3 years ago

Which division expression is equivalent to 4 1/3 ÷ -5/6

2 answers:

5 0

$4\dfrac{1}{3}\div\left(-\dfrac{5}{6}\right)\qquad(*)\\\\\text{Convert the mixed number to the improper fraction:}\\\\4\dfrac{1}{3}=\dfrac{4\cdot3+1}{3}=\dfrac{12+1}{3}=\dfrac{13}{3}\\\\(*)=\dfrac{13}{3}\div\left(-\dfrac{5}{6}\right)\\\\\text{By dividing by a fraction, we multiply by its reciprocal.}\\\\=\dfrac{13}{3}\cdot\left(-\dfrac{6}{5}\right)\qquad\text{simplify}\\\\=\dfrac{13}{3\!\!\!\!\diagup_1}\cdot\left(-\dfrac{6\!\!\!\!\diagup^2}{5}\right)=-\dfrac{13\cdot2}{1\cdot5}=-\dfrac{26}{5}=-\dfrac{25+1}{5}=-5\dfrac{1}{5}$

ss7ja [257]3 years ago

3 0

Answer:

the answer is 13/3 ÷ ( - 5/6 ) my luv :)

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Step-by-step explanation:

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A company advertises that its cans of caviar each contain 100 g of their product. A consumer advocacy group doubts this claim, a

Blizzard [7]

Answer:

The value of the test statistic is -3.14.

Step-by-step explanation:

Test statistic:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected value, $\sigma$ is the standard deviation and n is the size of the sample.

A company advertises that its cans of caviar each contain 100 g of their product.

This means that $\mu = 100$

They calculate a sample mean weight of 99 g and a sample standard deviation of 0.9 g. Sample of 8 cans.

This means that $X = 99, \sigma = 0.9, n = 8$

So the test statistic will be given by:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{99 - 100}{\frac{0.9}{\sqrt{8}}}$

$t = -3.14$

The value of the test statistic is -3.14.

8 0

3 years ago

True or false: Every kite is a rhombus, but not every rhombus is a kite.

horsena [70]

This is false. Kites can be shaped in many different ways so not all kites are rhombuses. Also, even the kites that look like rhombuses may not be rhombuses. Most kites have 2 pairs of sides with the same length. But, in order to be a rhombus all the sides have to be the same length but not all sides are the same length on a typical kite.

7 0

3 years ago

Can someone help me with this?

erik [133]

The equilibrium price is $12.

<h3>What is the equilibrium price ?</h3>

Equilibrium is the point where the quantity demanded is equal to the quantity supplied. The price at equilibrium is known as the equilibrium price and the quantity at equilibrium is known as the equilibrium quantity.

When shown on a graph, equilibrium is the point where the quantity demanded curve is equal to the quantity supplied curve.

When there is equilibrium, the equation of quantity demanded would be equal to the equation of quantity supplied.

-280 + 40p = 800 - 50p

In order to determine the value of p, take the following steps:

Combine similar terms: 800 + 280 = 40p + 50p

Add similar terms = 1080 = 90p

Divide both sides of the equation by 90 : 1080 / 90 = 12

To learn more about equilibrium, please check: brainly.com/question/26075805

#SPJ1

7 0

1 year ago

16 5x=31 what does x equal

liraira [26]

If you mean 165x = 31 , X = 0.19871794871
if you mean 16*5x = 31 , X = .3875
if you mean 16+5x=31 , X = 3
If you mean 16 -5x=31 , X = -3
Hope one of these is correct.

6 0

3 years ago

-3/v=-6 simply as much as possible

Aleksandr [31]

Hey!

In order to simplify this equation, we'll first have to multiply both sides of the equation by v. This will give us v on its own.

Original Equation :
$\frac{-3}{v} = -6$

New Equation {Added Multiply Both Sides by V} :
$\frac{-3}{v} v=-6v$

Solution {New Equation Solved} :
$-3 = -6v$

Now we'll switch sides to get v on the left side of the equation which is generally where we always want the variables to be located in these types of equations.

Old Equation :
$-3 = -6v$

New Equation {Switched} :
$-6v=-3$

Now we'll divide both sides by v to get v on its own.

Old Equation :
$-6v = -3$

New Equation {Added Divide Both Sides by V} :
$\frac{-6v}{v} = \frac{-3}{v}$

Solution {New Equation Solved} :
$v = \frac{1}{2}$

So, this means that in the equation $\frac{-3}{v} =-6$ , $v = \frac{1}{2}$ .

Hope this helps!

- Lindsey Frazier ♥

3 0

3 years ago