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Inessa05 [86]
3 years ago
8

Tobias’s closet has 1 red hat and 1 black hat; 1 white shirt, 1 black shirt, and 1 black-and-white-striped shirt; and 1 pair of

black pants and 1 pair of blue pants. He is picking an outfit by reaching into his closet and randomly choosing a hat, a shirt, and a pair of pants. How many possible outfit combinations are there?

Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0

Answer:

The answer is C on Edge The top answer is correct

Step-by-step explanation:

Took the quiz

Hope this helps!!!! :)

forsale [732]3 years ago
5 0

Answer:

There are total 12 outfit combinations.

Step-by-step explanation:

Number of hat are: 2

1 red hat and 1 black hat

Number of shirt are: 3

1 white shirt , 1 black shirt , 1 black-and-white striped shirt.

Number of pants are: 2

1 black and 1 blue

Now, the total number of combinations could be seen with the help of a tree diagram.

We observe that total 12 combinations are possible.

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3 years ago
Whats the answer & how do I solve it ?
Veseljchak [2.6K]

Answer:

Area of rectangle = 225/2 or 112.5

Step-by-step explanation:

Given,

Consider a rectangle ABCD.

Let AC be a diagonal of rectangle of length   = 15

In triangle  ABC.

Sin 45° =height/hypotenuse   {SinФ = height / hypotenuse}

Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)

And height is AB

Therefore, sin 45° = AB/AC

or sin 45° = AB / 15

or 1/√2 = AB /15

AB = 15/√2

Similarly we can find Base (i.e BC) using cosine.

Cos 45° = Base/Hypotenuse

Cos 45° = BC / AC

or  1/√2 = BC/15

BC = 15/√2

Hence we got length of rectangle , AB= 15/√2

And width of rectangle , BC = 15/√2

Therefore, area of rectangle = Length × Width

Area of rectangle = 15/√2  ×   15/√2  = 225/2

Hence, area of rectangle = 225/2 = 112.5

6 0
3 years ago
If the atomic number of an element is 7 and its mass number is 16, how many neutrons are in the atom's nucleus
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8 0
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Suppose y varies directly with x. If y = 6 when x = 2, find x when y = 12. 4 3
kobusy [5.1K]

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we also know that } \begin{cases} y=6\\ x=2 \end{cases}\implies 6=k(2)\implies \cfrac{6}{2}=k\implies 3=k \\\\\\ therefore\qquad \boxed{y=3x} \\\\\\ \textit{when y = 12, what is \underline{x}?}\qquad 12=3x\implies \cfrac{12}{3}=x\implies 4=x

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3 years ago
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