All categories

3 years ago

Help asap plsssssss

Mathematics

1 answer:

balu736 [363]3 years ago

4 0

Answer:

B.) Associative Property of Addition

Step-by-step explanation:

This is because none of the numbers change places the only things that move are the parenthesis which correspond with the associative property.

You might be interested in

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

2 years ago

Please help .

Iteru [2.4K]

702 can not be written as the product of 2 prime numbers, because if you divide 702 by 2 then you get 351 and that is not a prime number. Therefore 702 is a prime number.

8 0

3 years ago

I skipt thought the lesson pls help

Karo-lina-s [1.5K]

Answer:

I'm not sure but the last one I think is wroght

4 0

3 years ago

Read 2 more answers

Whoever helps me will be lucky for the rest of your life

Anvisha [2.4K]

Answer:

A) 3.5

16 shovels full

Step-by-step explanation:

9x + 13 = 17x - 15

8x = 28

x = 3.5

20 + 5x = 32 + 4.25x

0.75x = 12

x = 16

7 0

3 years ago

Monroe is gift wrapping a box that has the shape of a right rectangular prism. The box has a length of 20 cm, a width of 7 cm, a

Allisa [31]

I would assume you would do base*width*weight to get your area.

6 0

3 years ago

Help asap plsssssss ​

Help asap plsssssss