If you have any questions on what I did, just leave a comment.
I tried to add my second image but it won't allow me. So, the base is 6 that you're missing for question 6. Good luck.
Answer:
Option 1: 0.32
Step-by-step explanation:
Let
P(A) be the experimental probability of getting two
And
P(B) be the experimental probability of getting three
The dice is rolled 360 times.
So the sample space is n(S) = 360
P(A) = n(A)/n(S)
= 54/360
= 0.15
And
P(B) = n(B)/n(S)
= 62/360
= 0.172
As both the events A and B are mutually exclusive,
P(A or B) = P(A) + P(B)
= 0.15 + 0.172
=0.322
Rounding of to one decimal gives us:
0.32
So the probability of rolling a two or three is 0.32 ..
Answer:
An equation for the nth term of the arithmetic sequence 17, 12, 7, 2 is 17-5n.
Step-by-step explanation:
Given,
first term(a)=17
common difference (d)=t2-t1
=12-17
=-5
nth term of the arithmetic sequence = a+n×d
=17+n×-5
=17-5n
<em>-9</em><span><em>º </em>
You can figure this out by doing every thing backwards:
</span> –6º plus 3 degrees the minus <span>6 degrees</span>
