Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
1/2 (8+4)= 6
1/2(-1+4)= 1.5
1/2 (2+4)= 3
1/2 (4+4)= 4
So the correct answer would be A(8)
10 - nw is less than or equal to 8
n = number
Answer:
4.66666666667
Step-by-step explanation:
