We have that
<span>A (-8, -2) and B(16,6)
step 1
find the distance AB in the x coordinates
dABx=(16-(-8))-----> 24 units
step 2
find coordinate x of P (Px)
Px=Ax+(3/5)*dABx------> Px=(-8)+(3/5)*24----> 6.4
step 3
F</span>ind the distance AB in the y coordinates
dABy=(6-(-2))-----> 8 units
step 4
find coordinate y of P (Py)
Py=Ay+(3/5)*dABy------> Py=(-2)+(3/5)*8----> 2.8
the coordinates of P are (6.4,2.8)
see the attached figure
The awser for this problem im preety sure is going to be aswer c
Actually Welcome to the Concept of the Angles,.
Since,the AE is a angle bisector, hence, BAE = EAC simply.
hence we equate them..
===> x+ 30 = 3x - 10
==> 3x - x = 30 + 10
==> 2x = 40
==> x = 20°
hence the major angle EAC = 3(20)-10 = 60-10 = 50°
hence, angle EAC = 50°