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3 years ago

Find the distance. V(X2-X.)2+(2-Y.)? (1,2)(5,4) (-3,5)(2,3)

Mathematics

2 answers:

katrin2010 [14]3 years ago

8 0

Answer:

The distance formula is an algebraic expression used to determine the distance between two points with the coordinates (x1, y1) and (x2, y2).

Example

Find the distance between (-1, 1) and (3, 4).

This problem is solved simply by plugging our x- and y-values into the distance formula:

Sometimes you need to find the point that is exactly between two other points. This middle point is called the "midpoint". By definition, a midpoint of a line segment is the point on that line segment that divides the segment in two congruent segments.

If the end points of a line segment is (x1, y1) and (x2, y2) then the midpoint of the line segment has the coordinates: HOPES THIS HELPS

Step-by-step explanation:

Paha777 [63]3 years ago

4 0

Answer: If you divide a trinomial by a monomial the result is a bionomial

A. True

B. False

Step-by-step explanation: tell me the correct answer and I'll tell you

You might be interested in

Evaluate the given integral by changing to polar coordinates.

strojnjashka [21]

Answer:

The result of the integral is $\frac{\pi}{4}(\cos{4}-\cos{1})$

Step-by-step explanation:

Polar coordinates:

In polar coordinates, we have that:

$r^2 = x^2 + y^2$

$\int \int_{R} dA = \int \int_{R} r dr d\theta$

In which r is related to the radius values, while $\theta$ is related to the angles in the trigonometric circle.

In this question:

R is the region in the first quadrant

In the first quadrant in the trigonometric circles, the angles go from 0 to $\frac{\pi}{2}$ , which means that this are the outer limits of integration.

Between the circles with center the origin and radii 1 and 2

This means that the inner limits of integration are between 1 and 2.

The integral will be given by:

$\int \int_{R} \sin{x^2+y^{2}} dA = \int_{0}^{\frac{\pi}{2}} \int_{1}^{2} \sin{r^2} r dr d\theta$

Inner integral:

$\int_{1}^{2} \sin{(r^2)} r dr$

By substituion,

$u = r^2$

$du = 2r dr$

$dr = \frac{du}{2r}$

$\int_{1}^{2} \sin{(r^2)} r dr = \int_{1}^{2} \sin{u} r \frac{du}{2r}$ = \frac{1}{2} \int_{1}^{2} \sin{u} du[/tex]

Integral of sine is minus cosine. So

$\frac{1}{2}(\cos{u})|_{1}^{2}$

Before replacing, we substitute back u.

$\frac{1}{2}(\cos{r^2})|_{1}^{2} = \frac{1}{2}(\cos{4}-\cos{1})$

Outer integral:

$\int_{0}^{\frac{\pi}{2}} \frac{1}{2}(\cos{4}-\cos{1}) d\theta$

$\frac{\theta}{2}(\cos{4}-\cos{1})_{0}^{\frac{\pi}{2}}$

$\frac{\pi}{4}(\cos{4}-\cos{1})$

The result of the integral is $\frac{\pi}{4}(\cos{4}-\cos{1})$

3 0

3 years ago

Carlos swam to the bottom of a pool that is 12 feet deep. What is the opposite of Carlos elevation relative to the surface.

MariettaO [177]

The Anwser Is -12 Because He Swam 12 Feet Deep And It Would Not Be The Other Answers Because He Did Not Swim More Down Into The Pool So It Would Be -12

5 0

3 years ago

Read 2 more answers

Help me please and this

vlada-n [284]

You should choose plumber B

7 0

3 years ago

Read 2 more answers

I need help with this is there anyone

olga nikolaevna [1]

Angle 1&3 is 70° becuase 180-110= 70

Angle 4 is 110° becuase it is the alternate exterior angle to Angle 2, which equals 110°.

Hope this helps!

3 0

3 years ago

Time is now 11:45 AM what is the smaller angle between hour and minute hand on o'clock

Crazy boy [7]

Given that the time now is 11:45 a.m, the smallest and between the hour and minute hand on the o'clock will be given by:
60 min=360 degrees
the time between the min hand and the hour hand is 10 min;
thus the angle will be:
10/60*360
=60 degrees

3 0

4 years ago