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aev [14]
3 years ago
5

3x^2-4=7x standard form in quadratic ?

Mathematics
2 answers:
LenaWriter [7]3 years ago
7 0
3x^2-4=7x is the answer
Natalka [10]3 years ago
5 0
<span>3x^2 - 4 = 7x is the standard form. To get standard form into quadratic you must have one side of the equation equal zero. The easiest way to so is subtracting 7x on both sides of the equation.

</span><span>3x^2 - 4 = 7x
        -7x   -7x

3x^2 -7x - 4 = 0 

So, </span>3x^2 -7x - 4 = 0 is the quadratic form.
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jeka94

Answer:

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Step-by-step explanation:

The unknown triangle is half of the size of the original triangle, The right side measurement basically hints to the actual answer.

5 0
3 years ago
What is the answer for m^2-5m-14=0?
tensa zangetsu [6.8K]

Answer: m = 7 or -2

Step-by-step explanation:

Quadratic Formula!  \frac{{-b (+/-)\sqrt{(b^{2}-4ac }}}{2a}

Polynomial Form: ax^{2} +bx+c

So in this example a: 1  b: -5  c: -14

You get:\frac{{-(-5) (+/-)\sqrt{((-5)^{2}-4(1)(-14) }}}{2(1)}

m = 7 or -2

Check by plugging a value back in for m

(7)^{2} -5(7)-14=0?\\(-2)^{2} -5(-2)-14=0?\\

True for both.

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