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3 years ago

We want to factor the following expression:

Mathematics

1 answer:

horsena [70]3 years ago

3 0

Answer:

We can't use any of the patterns.

Step-by-step explanation:

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This net can be folded to make a square pyramid. what is the surface area of the pyramid

givi [52]

Answer:

$85in^2$

Step-by-step explanation:

to find the surface area we need to find the followng areas:

area of the square

area of a triangle and multiply it by 4 (because there are 4 triangles)

And once we have those areas, we add them to find the surface area.

Area of the square:

the formula to find the area of a square is:

$a_{square}=l^2$

where $l$ is the length of the side: $l=5in$

thus the area of the square is:

$a_{square}=(5in)^2$

$a_{square}=25in^2$

Area of the triangles:

the are of 1 triangle is given by

$a_{triangle} =\frac{b*h}{2}$

where $b$ is the base of the triangle: $b=5in$ (the base of the triangle is the side of the square)

and $h$ is the height of the triangle: $h=6in$

thus, the area of 1 triangle is:

$a_{triangle} =\frac{(5in)*(6in)}{2}$

$a_{triangle} =\frac{30in^2}{2}$

$a_{triangle} =15in^2$

the area of the 4 triangles is (we multiply by 4):

$a_{4-triangles}=4(15in^2)$

$a_{4-triangles}=60in^2$

finally we add the area of the square and the area of the 4 triangles to find the total surface area:

$Surface=25in^2+60in^2$

$Surface=85in^2$

8 0

2 years ago

Whats the area of the triangle? (10,8,12.8)

statuscvo [17]

Answer:

LXBXH

AREA=10X8X12.8

AREA=1024

4 0

2 years ago

Trigonometry help!! - double angle formulae

ivolga24 [154]

Answer:

The two rules we need to use are:

Sin(a + b) = sin(a)*cos(b) + sin(b)*cos(a)

cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)

And we also know that:

sin^2(a) + cos^2(a) = 1

To solve the relations, we start with the left side and try to construct the right side.

a) Sin(3*A) = sin (2*A + A) = sin(2*A)*cos(A) + sin(A)*cos(2*A)

sin(A + A)*cos(A) + sin(A)*cos(A + A)

(sin(A)*cos(A) + sin(A)*cos(A))*cos(A) + sin(A)*(cos(A)*cos(A) - sin(A)*sin(A))

sin(A)*cos^2(A) + sin(A)*cos^2(A) + sin(A)*cos^2(A) - sin^3(A)

3*sin(A)*cos^2(A) - sin(A)*sin^2(A)

sin(A)*(3*cos^2(A) - sin^2(A))

Now we can add and subtract 4*sin^3(A)

sin(A)*(3*cos^2(A) - sin^2(A)) + 4*sin^3(A) - 4*sin^3(A)

sin(A)*(3*cos^2(A) + 3*sin^2(A)) - 4*sin^3(A)

sin(A)*3*(cos^2(A) + sin^2(A)) - 4*sin^3(A)

3*sin(A) - 4*sin^3(A)

b) Here we do the same as before:

cos(3*A) = 4*cos^3(A) - 3*cos(A)

We start with:

Cos(2*A + A) = cos(2*A)*cos(A) - sin(2*A)*sin(A)

= cos(A + A)*cos(A) - sin(A + A)*sin(A)

= (cos(A)*cos(A) - sin(A)*sin(A))*cos(A) - ( sin(A)*cos(A) + sin(A)*cos(A))*sin(A)

= (cos^2(A) - sin^2(A))*cos(A) - sin^2(A)*cos(A) - sin^2(A)*cos(A)

= cos^3(A) - 3*sin^2(A)*cos(A)

= cos(A)*(cos^2(A) - 3*sin^2(A))

now we subtract and add 4*cos^3(A)

= cos(A)*(cos^2(A) - 3*sin^2(A)) + 4*cos^3(A) - 4*cos^3(A)

= cos(A)*(-3*cos^2(A) - 3*sin^2(A)) + 4*cos^3(A)

= cos(A)*(-3)*(cos^2(A) + sin^2(A)) + 4*cos^3(A)

= -3*cos(A) + 4*cos^3(A)

8 0

3 years ago

53 1/3 in the form 53^n where n is a whole number

horsena [70]

5 0

2 years ago

9.<br> Kyle ran 150 feet in 15 seconds, how many hours would it take him to<br> run 30 miles?

PtichkaEL [24]

She runs 30 miles in 3 seconds

8 0

3 years ago

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