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4 years ago

Intersecting lines forming linear pair which pair of angles is a linear pair?

Mathematics

1 answer:

Mekhanik [1.2K]4 years ago

7 0

The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

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What is the total surface area of a right circular cylinder with base radius 7cm and height 12cm.

mojhsa [17]

Answer:

Using 3.14 for pi

835.24 cm^2

Using the pi button for pi

835.6636459 cm^2

Step-by-step explanation:

The surface area of a cylinder is given by

SA = 2 pi r^2 + 2 pi r h

= 2 * pi ( 7)^2 + 2 pi ( 7) * 12

= 98 pi + 168 pi

=266 pi

Using 3.14 for pi

835.24 cm^2

Using the pi button for pi

835.6636459 cm^2

8 0

4 years ago

Read 2 more answers

If I worked 8 hours and 49 minutes but my paycheck was only 97.17$ what was my hourly wage.

ruslelena [56]

Answer:

11.021$

Step-by-step explanation:

49min to hr=49/60=0.816

now total worked hrs =8hr +0.816hr=8.166hr

now 1hr wage =97.17$/total hr(8.166)=11.021$

7 0

3 years ago

a cylinder has a base radius of 2 inches and a height of 9 inches what is the volume in cubic in to the nearest tenth place.

GuDViN [60]

Answer:

113.1 cubic inches

Step-by-step explanation:

The volume of a cylinder is given by the formula:

$V=\pi r^2 h$

Where

V is the volume

r is the radius

h is the height

Given, h = 9 and r = 2, we substitute and find the volume:

$V=\pi r^2 h\\V=\pi (2)^2 (9)\\V=36\pi\\V=113.097$

We need answer to nearest tenth, that is 1 decimal place, so we round of the answer as:

113.1 cubic inches

3 0

3 years ago

In a certain county, the number of charter schools is 6 less than twice the number of atternative schools. We know that there ar

posledela

C = 2A - 6
C = 52

52 = 2A - 6
52 + 6 = 2A
58 = 2A
58/2 = A
29 = A <==alternative schools

7 0

4 years ago

7.1 A player throws a fair die and simultaneously flips a fair coin. If the coin lands heads, then she wins twice, and if tails,

Tcecarenko [31]

Answer:

1.875

Step-by-step explanation:

To find the expected winnings, we need to find the probability of all cases possible, multiply each case by the value of the case, and sum all these products.

In the die, we have 6 possible values, each one with a probability of 1/6, and the value of each output is half the value in the die, so we have:

$E_1 = \frac{1}{6}\frac{1}{2} + \frac{1}{6}\frac{2}{2} +\frac{1}{6}\frac{3}{2} +\frac{1}{6}\frac{4}{2} +\frac{1}{6}\frac{5}{2} +\frac{1}{6}\frac{6}{2}$

$E_1 = \frac{1}{12}(1+2+3+4+5+6)$

$E_1 = \frac{21}{12} = \frac{7}{4}$

Now, analyzing the coin, we have heads or tails, each one with 1/2 probability. The value of the heads is 2 wins, and the value of the tails is the expected value of the die we calculated above, so we have:

$E_2 = \frac{1}{2}2 + \frac{1}{2}E_1$

$E_2 = 1 + \frac{1}{2}\frac{7}{4}$

$E_2 = 1 + \frac{7}{8}$

$E_2 = \frac{15}{8} = 1.875$

3 0

3 years ago