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Mnenie [13.5K]
3 years ago
13

Find the first 3 iterations using f(x)=3x if you have an initial value of 1 show work

Mathematics
1 answer:
enot [183]3 years ago
7 0

Answer:

You need to replace the x with the value that you want to evaluate. If the initial value is 1, you have to replace the x with1, then with 2, an finally with 3.

<em>Iteration 1.</em>

f(x=1)=3*(1)

f(x=1)=3

<em>Iteration 2.</em>

f(x=2)=3*(2)

f(x=2)=6

<em>Iteration 3.</em>

f(x=3)=3*(3)

f(x=3)=9

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Find x<br> 25<br> 7<br> х<br> I need help
Murljashka [212]

Answer:

24 = x

Step-by-step explanation:

You use Pythagorean theorem. Since the normal equation is a^{2} + b^{2} =c^{2}, you already have the c^{2} and another side which can be a^{2} or b^{2}.

Because you have the hypotenuse and a side , your equation looks like this now: 7^{2} +b^{2} = 25^{2}

and when you solve for be you just subtract 25^{2} -7^{2} to get 24.

8 0
2 years ago
Add 8x+6yz-3zx, 4yz+6zx-8y, -3xz+6x-4xy<br><br> pls find answer...
Butoxors [25]
Na bro i dont even know what’s that tbh
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2 years ago
Simplify each expression. Use positive exponents. <br> A^4b^-3<br> ab^-2
choli [55]
\dfrac{a^4b^{-3}}{ab^{-2}}

= {a^{4-1}b^{-3+2}}

= {a^{3}b^{-1}}

= \dfrac{a^3}{b}


6 0
2 years ago
Read 2 more answers
5. 6(2+ y)=3(3- y)<br> Help
Maurinko [17]

Answer:

Step-by-step explanation:

4 0
3 years ago
Can anyone please help me in this
Alik [6]

These problems are called systems of equations. Basically you have two linear equations and you need to find the values for x and y. In other words, all these equation are lines and our answer will be the exact point that the pair of lines intersect. For example, if we get x=1 and y=2 the lines will intersect at point (1,2). Now that you have some background knowledge here comes the tricks and tactics kid.

We know that we can solve one variable equation easily. For example...

x+1=2

x=1 obviously

Cause we have two variables x and y it is not possible to find a solution. For example, in the equation x+y=10, x=1 when y=9 and x=2 when y=8. There is not correct answer.

So what can we do? We have to make a two variable equation into a one variable equation.

There are two ways to do this: substitution and elimination. I will create a sample problem and then solve it using both methods.

x+y=2

2y-y=1

3)  

-3x-5y=-7 -----> -12x-20y=-28

-4x-3y=-2 ------> -12x-9y=-6

 -12x-20y=-28

-(-12x-9y=-6)

---------------------

-11y=-22

y=2

-3x-5(2)=-7

-3x=3

x=-1

4) 8x+4y=12 ---> 24x+12y=36

7x+3y=10 ---> 28x+12y=40

 28x+12y=40

-(24x+12y=36)

---------------------

4x=4

x=1

8(1)+4y=12

4y=4

y=1

5) 4x+3y=-7

-2x-5y=7 ----> -4x-10y=14

    4x+3y=-7

+(-4x-10y=14)

-------------------

-7y=7

y=-1

4x+3(-1)=-7

4x=-4

x=-1

6) 8x-3y=-9 ---> 32x-12y=-36

5x+4y=12 ---> 15x+12y=36

 32x-12y=-36

+(15x+12y=36)

--------------------

47x=0

x=0

8(0)-3y=-9

-3y=-9

y=3

7)-3x+5y=-2

2x-2y=1 ---> x-y=1/2 ----> x=y+1/2

-3(y+1/2)+5y=-2

-3y-1.5+5y=-2

2y=-0.5

y=0.25

2x-2(0.25)=1

2x=1.5

x=0.75

4 0
3 years ago
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