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Stella [2.4K]
3 years ago
15

Classify the quadrilateral. Then find the value(s) of the variable(s). PLEASE HELP

Mathematics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

A

Step-by-step explanation:

plug in y and x, if you want to be sure of each answer

In the case of A) here are the 2 equations, y-2=x+4 and 3x+4=x+6

now plug in what a describes

x=1, y=7

7-2=1+4 and 7=7

Therefore the answer is A  

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Round to the nearest whole number 486.3÷8.1
PolarNik [594]

Answer: 60.


Step-by-step explanation: After you divide you get 60.037037. And since were rounding its 60.


4 0
4 years ago
Suppose that w and t vary inversely and that t = 5/12
Svetlanka [38]

Answer:

Option B. t=5/3w ;1/3

Step-by-step explanation:

We are told that w varies Inversely with t thus generally speaking w∝\frac{1}{t}  since they are inverted, <u>otherwise</u> if they were proportionally varied then w∝t. This means that there is a constant value ( a ) for which w is inversely proportional to t and can be mathematically expressed as:

w=\frac{a}{t}        Eqn. (1)

Now since we are given the values of w=4 and t=\frac{5}{12}, we can plug them in Eqn. (1) and find our constant of proportionality a as follow:

w=\frac{a}{t}\\ \\a=wt\\\\a=(4)(\frac{5}{12} )\\\\a=\frac{5}{3}

Now that we have our constant we can find the new t value for the second value of w=5 as follow:

w=\frac{a}{t} \\\\t=\frac{a}{w}\\ \\t=\frac{\frac{5}{3} }{5}\\\\t=\frac{5}{15}\\ \\t=\frac{1}{3}\\

Therefore based on the options give, we can see that Option B. is correct since

t=\frac{5}{3w} and for w=5, then t=\frac{1}{3}

8 0
3 years ago
I need the angle of elevation
Aleksandr-060686 [28]

Answer:

multiply and see what you get

4 0
3 years ago
Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE. A horizontal line has points C, F, E, G. 2 lines extend from
zaharov [31]

Answer:

\angle CFD =105^o

Step-by-step explanation:

Given

\angle D FE = \angle DE F = 75^o

See attachment

Required

Determine the measure of \angle CFD

\angle CFD and \angle DFE are on a straight line.

So:

\angle CFD + \angle DFE = 180^o --- angle on a straight line

Substitute known values

\angle CFD + 75^o = 180^o

Collect like terms

\angle CFD =- 75^o + 180^o

\angle CFD =105^o

5 0
3 years ago
Read 2 more answers
Helpppppppppppppppppppppppppppppppp 50 points will give brainlyest to who answers first
denis23 [38]

Answer:

boom I hope this was the right thing

Step-by-step explanation:

i went on your profile thing yep

8 0
3 years ago
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