Question

Find the inverse of the function y = 2x^2+2

Answer 1

Answer:  (It could just be the first one you did not give enough information for your question so I wasn't sure)

$\sqrt{\frac{x-2}{2} } , -\sqrt{\frac{x-2}{2} }$

Step-by-step explanation:

Replace y with x:

$y=2x^{2} +2$   ⇒   $x=2y^{2} +2$

Subract 2 from both sides:

$x-2=2y^{2} +2 -2$   ⇒   $x-2=2y^{2}$

Divide 2 from both sides:

$\frac{x-2}{2} = \frac{2y^{2} }{2}$   ⇒   $\frac{x-2}{2} =y^{2}$

Square root both sides:

$\sqrt{\frac{x-2}{2} } =\sqrt{y^{2} }$    ⇒  $y=\sqrt{\frac{x-2}{2} }$

I hope this helps you have a bright blessed day.