Question

:

Answer 1

There was 4.35% error in Diego's measurements.

Step-by-step explanation:

Given,

Length measured by Diego = Approx value = 22 cm

Actual length = Exact value = 23 cm

Percent error = $\frac{|approx-exact|}{exact}*100$

$Percent\ error = \frac{|22-23|}{23}*100\\\\Percent\ error = \frac{|-1|}{23}*100\\\\Percent\ error = \frac{1}{23}*100\\\\Percent\ error = \frac{100}{23}\\\\Percent\ error = 4.347\%$

Rounding off to nearest hundredth

Percent error = 4.35%

There was 4.35% error in Diego's measurements.

Keywords: percentage, subtraction

Learn more about percentages at:

• brainly.com/question/13063819
• brainly.com/question/13219835

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