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3 years ago

13

What is the simplified form of (cube root of)16

1 answer:

xeze [42]3 years ago

5 0

Remember that $\sqrt[n]{x^m}= x^{ \frac{n}{m} }$ so

∛16=16^(1/3)
we know that
16=2^3 so
(2^3)^(1/3)
remember another rule
(x^m)^n=x^(mn) so
(2^3)^(1/3)=2^(3/3)=2^1=2

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