The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
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Answer:
x = 5.6 or you can write like this: x = 5 3/5
Step-by-step explanation:
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Answer:
(1) -5 and -3
Step-by-step explanation:
Descarte's rule of signs tells you the lack of sign changes among the coefficients means there are <em>no positive real roots</em>. That eliminates all answer choices except the first one.
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If you want to go to the trouble, you can factor the equation:
y = (x +3)(x +5)
These factors are zero when x = -5 and x = -3.
