Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
The answer is 1.5 bc 0.75 times 2 since it’s the midpoint
1.They basically all did one big bug,not separate hugs with different bears.
Answer:
7 1/8
Step-by-step explanation:
Assuming that the first 13 was a mistake then the equation would be 13 1/2 + 2n = 27 3/4
subtrace 13 1/2 from 27 3/4
14 1/4
divide by 2
7 1/8