It is possible to arrange the total of mangoes by using 20 piles of 9 mangoes, 18 piles of 10 mangoes, or 15 piles of 12 mangoes.
<h3>What are the different ways the mangoes can be arranged?</h3>
The conditions for mangoes to be arranged are that the piles should have either 9, 10 or 12 mangoes and reminders are not allowed. This means you need to fit all the mangoes and no mangoes can be left.
Based on the conditions and the total number of mangoes (180 mangoes), here are the possibilities that you can determine using division:
- 9 mangoes piles: 180/ 9 = 20 piles (9 x 20 = 180 with no remainders)
- 10 mangoes piles: 180/10 = 18 piles (10 x 18 = 180 with no remainders)
- 12 mangoes piles: 180/12 = 15 piles (12 x 15 = 180 with no remainders)
Learn more about division in brainly.com/question/369266
#SPJ1
The answer to this would be 250... Because a coin has 2 sides, the coin would land on either side about 250 times.
Answer:
-3 is a solution.
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
3 - 4r ≥ 15
<u>Step 2: Solve for </u><em><u>r</u></em>
- [Subtraction Property of Equality] Subtract 3 on both sides: -4r ≥ 12
- [Division Property of Equality] Divide -4 on both sides: r ≤ -3
<u>Step 3: Compare</u>
- Substitute in <em>r</em>: -3 ≤ -3
This is true. -3 is less than <em>or equal to</em> -3.
Step-by-step explanation:
m<C = 90°
According to the laws of cosine,
c²= a²+b²-2ab. cos(C)
c²=a²+b²-2ab.cos(90°)
c²=a²+b²-2ab.0 { cos(90°)= 0}
c²=a²+b²
a²=c²-b²
Answer:
EFD=52°
CFD=43°
Step-by-step explanation:
85° × 2= 170°
360°-170°=190°
190°÷2= 95°
6x-20+2x+19=95°
8x-1=95°
x=(95°+1)÷8
x= 12
EFD=6x-20
EFD= 6×12-20
EFD= 52°
CFD= 2x+19
CFD=2×12+19
CFD= 43°