HELP THIS IS WORTH 88 POINTS
1 answer:
You might be interested in
We have that
<span>vertex (0,0)
and
focus (2.5, 0)
we know that
</span>vertex and focus lie on same vertical or horizontal line
<span>in this problem
</span>We can see that focus is right of vertex so parabola opens to right. It is horizontal parabola
<span>the equation is of the form
(y-k)</span>²=4a(x-h)
<span>where (h,k)-----> is the vertex
and
a------> </span>distance between vertex and focus
<span>
step 1
vertex (h,k)-------> (0,0)
step 2
find the distance a between point (0,0) and (2.5, 0)
a=</span>√[(0-0)²+(2.5-0)²]------> a=√(2.5)²------> a=2.5 units
<span>
the equation is
</span>(y-k)²=4a(x-h)------> (y-0)²=4*2.5*(x-0)-------> y²=10x
<span>
the answer is
</span> y²=10x
<span>
see the attached figure
</span>
<span>vertex (0,0)
and
focus (2.5, 0)
we know that
</span>vertex and focus lie on same vertical or horizontal line
<span>in this problem
</span>We can see that focus is right of vertex so parabola opens to right. It is horizontal parabola
<span>the equation is of the form
(y-k)</span>²=4a(x-h)
<span>where (h,k)-----> is the vertex
and
a------> </span>distance between vertex and focus
<span>
step 1
vertex (h,k)-------> (0,0)
step 2
find the distance a between point (0,0) and (2.5, 0)
a=</span>√[(0-0)²+(2.5-0)²]------> a=√(2.5)²------> a=2.5 units
<span>
the equation is
</span>(y-k)²=4a(x-h)------> (y-0)²=4*2.5*(x-0)-------> y²=10x
<span>
the answer is
</span> y²=10x
<span>
see the attached figure
</span>