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Mila [183]
3 years ago
9

Please help me please please

Mathematics
1 answer:
aliina [53]3 years ago
8 0
We have to consider the Order of Operations
And Divide the question into different parts
So we first do the Exponent: 2^{5} = 32
(3×32-26)=(96-26)=70
Solve the parts in parenthesis 
(8-(4-9)=(8-(-5)=(8+5)=13 (minus and minus becomes addition)
Distribute 7
7(13)=91
Now put the equation and equate everything
(3×2^{5}+13(-2))+7(8-(4-9)=70+91=161
Final Answer=161

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If an intravenous solution containing 123 mg of a drug substance in each 250-mL bottle is to be administered at the rate of 200
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Answer:

24.39mL of the solution would be given per hour.

Step-by-step explanation:

This problem can be solved by direct rule of three, in which there are a direct relationship between the measures, which means that the rule of three is a cross multiplication.

The first step to solve this problem is to see how many mg of the solution is administered per hour.

Each minute, 200 ug are administered. 1mg has 1000ug, so

1mg - 1000 ug

xmg - 200 ug

1000x = 200

x = \frac{200}{1000}

x = 0.2mg

In each minute, 0.2 mg are administered. Each hour has 60 minutes. How many mg are administered in 60 minutes?

1 minute - 0.2 mg

60 minutes - x mg

x = 60*0.2

x = 12mg

In an hour, 12 mg of the drug is administered. In 250 mL, there is 123 mg of the drug. How many ml are there in 12 mg of the drug.

123mg - 250mL

12 mg - xmL

123x = 250*12

x = \frac{250*12}{123}

x = 24.39mL

24.39mL of the solution would be given per hour.

7 0
3 years ago
Can anyone please help me with this?
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Answer:

I believe that It would be b

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How can you determine which of two lines will be steeper from
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A new medical test provides a false positive result for hepatitis 2% of the time that is a perfectly healthy subject being teste
Oxana [17]
Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.

The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02


Part A:

</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:

</span>P(X)={ ^nC_xp^x(1-p)^{n-x}} \\  \\ P(0)={ ^{30}C_0(0.02)^0(1-0.02)^{30-0}} \\  \\ =1(1)(0.98)^{30}=0.5455
<span>

Part B:

The mean of a binomial distribution is given by

</span>\mu=np \\  \\ =30(0.02) \\  \\ =0.6
<span>
The standard deviation is given by:

</span>\sigma=\sqrt{np(1-p)} \\ \\ =\sqrt{30(0.02)(1-0.02)} \\ \\ =\sqrt{30(0.02)(0.98)}=\sqrt{0.588} \\  \\ =0.7668
<span>

Part C:

This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>
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