When we are given a line cutting diagonally from one corner of a rectangle to the opposite corner, we are given two triangles.
300ft
____
| /|
| / |
| / |
| / |400ft
| / |
| / |
|/ |
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*not to scale
Now, using the right-angle trigonometry rule, we can find the hypotenuse (the diagonal line) which represents the footpath.
a^2 + b^2 = c^2
{where a is one side length, b is another side length, and c is the hypotenuse}
Thus, we make c the subject of the equation and substitute the other known values:
c^2 = 400^2 + 300^2
= 160,000 + 90,000
= 250,000
Now we move the 'squared' (^2) from the left hand side to the right hand side. When moving it across the equal sign (=) the result becomes the 'root' of itself:
c = _/250,000
= 500
Therefore, the length of the diagonal path is 500ft.
Answer:
biconditional
Step-by-step explanation:
when are you asked for me thats wrong word bi uncountable only one wright word Conditional
Using the Pythagorean Theorem, it is found that the base of the pole should be set 10 feet from the end of the wire.
<h3>What is the Pythagorean Theorem?</h3>
The Pythagorean Theorem relates the length of the legs
and
of a right triangle with the length of the hypotenuse h, according to the following equation:

In this problem, the distance is
, while the other measures are
, hence:



The base of the pole should be set 10 feet from the end of the wire.
More can be learned about the Pythagorean Theorem at brainly.com/question/654982
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The answer is 9.0 because 8.5 is above 5 and to the nearest tenth it would be 9.0
Answer:
Step-by-step explanation:
The distance from one score to another tends to increase, and a single score tends to provide a less accurate representation of the entire distribution.
Consider normal distribution it has increasing trend from -Inf to the mean. But has no probability at any point. But if you consider binomial distribution then you will get the information at any integer of its range, but not all values of real line. That is you will not have information on (0,1) so there you cannot comment for increment of that distribution.