Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
The 2nd place after(to the right) the decimal. For example: .01. 1 would be in the hundredth place.
It would be 2,5, and 6. The mode means the number that is repeating the most. Since 2, 5, and 6 all appear 3 times, that is the mode
I really need one too. Thanks for the question.
Answer: B. positive 6
Step-by-step explanation: Addomg the positive number to a negative number would turn it to a positive eventually. So u covert your factions to decimals to better see the resemblance. And 1 1/2 is the same as 1.5, and 2 1/10 is the same as 2.1 but it’s easier to deal with decimals. So then just add the positive to the negative sense 1 1/2 is closer to zero. I hope this helps I’m not the best at explaining things
