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3 years ago

You have 20 bucks in your pocket.

Mathematics

1 answer:

diamong [38]3 years ago

5 0

Answer:

the answer would be $45.55

Step-by-step explanation:

20$ + $50.00 = $70

$70 - $6.95 = $64.5

$64.5 - $9.95 = $54.55

$54.55 - $20 = $34.55

$34.55 + $15 = $49.55

$49.55 - $4 = $45.55

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A 5-pound sack of potatoes is supposed to weigh 5

TEA [102]

Answer:

t test for one mean.

met

Step-by-step explanation:

5 0

2 years ago

[-1/4/5] × [-7/10+0.95] - [-2/1/4]

const2013 [10]

Answer:

-2.5625

Step-by-step explanation:

1)[-1/4/5] × [-7/10+0.95] - [-2/1/4] turn that into improper fractions

2 1/4=9/4

which is 1 4/5(-7/10+0.95)9/4

2) 1 4/5(-7/10+0.95)= 0.3125

which is 0.3125-9/4

3)Make into decimal form

9/4 equals 2.25

which is 0.3125-2.25

which all equals -2.5625

5 0

3 years ago

True or false: randomization allows each member of the population to have an equal probability of being selected for the sample

tia_tia [17]

Answer:

True

Step-by-step explanation:

Simple random sampling chooses at random members of the population. This allows all members an equal probability of being selected for the sample.

4 0

3 years ago

Please hurry I am timed

rosijanka [135]

Answer:

I think its B

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Sand pouring from a chute forms a conical pile whose height is always equal to the diameter. If the height increases at a consta

Cerrena [4.2K]

Answer:

$125\pi \frac{\text{ft}^3}{\text{min}}$ .

Step-by-step explanation:

Let x represent height of the cone.

We have been given that Sand pouring from a chute forms a conical pile whose height is always equal to the diameter.

We know that radius is half the diameter, so radius of cone would be $\frac{x}{2}$ .

We will use volume of cone formula to solve our given problem.

$V=\frac{1}{3}\pi r^2h$

Upon substituting the value of height and radius in terms of x, we will get:

$V=\frac{1}{3}\pi (\frac{x}{2})^2(x)$

$V=\frac{1}{3}\pi\frac{x^2}{4}(x)$

$V=\frac{1}{12}\pi x^3$

Now, we will take the derivative of volume with respect to time as:

$\frac{dV}{dt}=\frac{1}{12}\pi\cdot 3x^2\cdot \frac{dx}{dt}$

$\frac{dV}{dt}=\frac{1}{4}\pi\cdot x^2\cdot \frac{dx}{dt}$

Upon substituting $x=10$ and $\frac{dx}{dt}=5$ , we will get:

$\frac{dV}{dt}=\frac{1}{4}\pi\cdot (10)^2\cdot 5$

$\frac{dV}{dt}=\frac{1}{4}\pi\cdot 100\cdot 5$

$\frac{dV}{dt}=\pi\cdot 25\cdot 5$

$\frac{dV}{dt}=125\pi$

Therefore, the sand is pouring from the chute at a rate of $125\pi \frac{\text{ft}^3}{\text{min}}$ .

8 0

3 years ago