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OLga [1]
3 years ago
7

If there are 13 values in a data set in order from smallest to largest, what is the third quartile of the data set?

Mathematics
1 answer:
Vikki [24]3 years ago
6 0
I am pretty sure the quartile is just the third number in a data set so it would 39? I do not recommend using this I am only 14 after all   <span />
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Write the expression in complete factored form. 2a(u+2)+9(u+2)=
KIM [24]

Answer:

(u+2)(2a+9)

Step-by-step explanation:

2a(u+2)+9(u+2)

Taking (u+2) common

We get

(u+2)(2a+9)

5 0
3 years ago
Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl
amm1812

Answer:

1. P(s_1|I)=\frac{1}{11}

2. P(s_2|I)=\frac{8}{11}

3. P(s_3|I)=\frac{2}{11}

Step-by-step explanation:

Given information:

P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3

P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1

(1)

We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}

P(s_1|I)=\frac{0.015}{0.165}

P(s_1|I)=\frac{1}{11}

Therefore the value of P(s₁|I) is \frac{1}{11}.

(2)

We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}

P(s_2|I)=\frac{0.12}{0.165}

P(s_2|I)=\frac{8}{11}

Therefore the value of P(s₂|I) is \frac{8}{11}.

(3)

We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}

P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

Therefore the value of P(s₃|I) is \frac{2}{11}.

4 0
3 years ago
Which value is equivalent to x+4/4+x?<br><br> A. -4<br> B. -1<br> C. 1<br> D. 4
MaRussiya [10]

Answer:

Hello :

(x+4)/(4+x) = (x+4)/(x+4)  = 1   ( answer : C )  but x+4 no : 0



3 0
3 years ago
Read 2 more answers
The height of a triangle is two more than three times the base. Determine the dimensions that will give a total area of 28 yards
jonny [76]
H = 3b+2
A = (h*b)/2     28 = (3b+2)b/2     56 = 3b²+2b    0 = 3b² + 2b - 56

⊕\left \{ {{y=2} \atop {x=2}} \right.  \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_n   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \beta  \\  \\  \\  x^{2}  \sqrt{x}  \sqrt[n]{x}  \frac{x}{y}  x_{123}  x^{123}  \leq  \geq  \pi  \alpha   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  x_{123}  \int\limits^a_b {x} \, dx  \left \{ {{y=2} \atop {x=2}}
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8 0
3 years ago
What is the factored form of x^3 -1
lianna [129]

Answer:

The factored form of x^3 -1 will be:

x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)

Step-by-step explanation:

Given the expression

x^3-1

Rewrite 1 as 1³

=x^3-1^3

\mathrm{Apply\:Difference\:of\:Cubes\:Formula:\:}x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)

x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)

            =\left(x-1\right)\left(x^2+x+1\right)

Thus, the factored form of x^3 -1 will be:

x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)

8 0
3 years ago
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