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VashaNatasha [74]
4 years ago
11

Someone please help me

Mathematics
1 answer:
wel4 years ago
3 0
V=(hπr^2)/3, π≈3.14, h=7, r=2

V≈29.3 cm^2
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Please help me solve this, and show your work
zlopas [31]

6r+5=11r\ \ \ \ |\text{subtract 6r from both sides}\\\\5=5r\ \ \ \ |\text{divide both sides by 5}\\\\\boxed{r=1}\\-------------------------\\\dfrac{2x-4}{2}=6x+3\\\\\dfrac{2x}{2}-\dfrac{4}{2}=6x+3\\\\x-2=6x+3\ \ \ \ \ |\text{add 2 to both sides}\\\\x=6x+5\ \ \ \ |\text{subtract 6x from both sides}\\\\-5x=5\ \ \ \ \ |\text{divide both sides by -5}\\\\\boxed{x=-1}

6 0
4 years ago
Which expression represents the phrase "twice the difference of a number and 5"?
Molodets [167]

Answer:

2 (x - 5)

I hope this helps u.

Step-by-step explanation:

8 0
3 years ago
The table shows the outputs y for different inputs x:
kirill [66]
Part A:

For a table to be considered a function, every x-value must have one y-value. 
Each x-value in this table is unique, and has only one y-value, so this table does represent a function.

Part B:

Plug in 7 for every x in the relation:

2(7) + 13 = 14 + 13 = 27

The table's output when x = 7 is 11. Compare the two outputs:

11 < 27

The relation, 2x + 13, has a greater value when x = 7.

Part C:

Set the relation to equal 75:

2x + 13 = 75

Subtract 13 from both sides:

2x = 62

Divide both sides by 2 to get x by itself:

\boxed{x = 31}

The x value that produces an output of 75 will be 31.
4 0
4 years ago
Write an equation in point slope form for the line through the given point with the given slope (4,-6); m=3/5
77julia77 [94]
The\ point-slope\ form:y-y_1=m(x-x_1)\\---------------------\\m=\frac{3}{5}\\\\(4;-6)\to x_1=4\ and\ y_1=-6\\\\subtitute:\\\\y-(-6)=\frac{3}{5}(x-4)\\\\\boxed{y+6=\frac{3}{5}(x-4)}
4 0
3 years ago
Read 2 more answers
A data set includes data from student evaluations of courses. The summary statistics are n​, ​, s. Use a significance level to t
Andru [333]

Complete question :

A data set includes data from student evaluations of courses. The summary statistics are nequals92​, x overbarequals4.09​, sequals0.55. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

Answer:

H0 : μ = 4.25

H1 : μ < 4.25

T = - 2.79

Pvalue =0.0026354

we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%

Step-by-step explanation:

Given :

n = 92​, xbar = 4.09​, s = 0.55 ; μ = 4.25

H0 : μ = 4.25

H1 : μ < 4.25

The test statistic :

T = (xbar - μ) ÷ s / √n

T = (4.09 - 4.25) ÷ 0.55/√92

T = - 0.16 / 0.0573414

T = - 2.79

The Pvalue can be obtained from the test statistic, using the Pvalue calculator

Pvalue : (Z < - 2.79) = 0.0026354

Pvalue < α ; Hence, we reject the Null

Thus, we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%

4 0
3 years ago
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