You have to use the equation which has just slipped my mind. It say x1-y1 over x2-y2. Then you will find x. I am so sorry this equation name slipped my mind. If I remember I will let you know.
We can use the Pythagorean theorem to solve for the perimeter of the kite.
a² + b² = c²
3² + 4² = UV²
9 + 16 = UV²
25 = UV²
√25 = √UV²
5 = UV
In the kite, adjacent sides are the same so UV = VW
3² + 9² = UX²
9 + 81 = UX²
90 = UX²
√90 = √UX²
9.49 ≈ UX or 3√10 ≈ UX
Now, add to find the perimeter.
5 + 5 + 9.49 + 9.49 or 5 + 5 + 3√10 + 3√10
28.98 or 10 + 6√10
Therefore, the perimeter is approximately 28.98 or 10 + 6√10
Best of Luck!
Since the painting is hung in center of a rectangular wall ,the distance between them on either side will be the same.so we can divide the length of the painting and wall by 2.we will get 2.4/2=1.2 feet and 20/2=10 feet .10-1.2=8.8 feet gives the distance between the right edge of the painting and right edge of the wall
Answer:
Step-by-step explanation:
x=140°
m || n
