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Liula [17]
3 years ago
10

Which logarithmic equation is equivalent to 2^5=32

Mathematics
1 answer:
stepan [7]3 years ago
3 0

Answer: 5=log_{2}(32)5=log

2

(32)

Step-by-step explanation:

1. By definition, you have if y=b^{x}y=b

x

, then x=log_{b}(y)x=log

b

(y)

2. Keeping this on mind, you must follow the proccedure shown below:

- You have that:

2^{5}=322

5

=32

Where:

\begin{lgathered}x=5\\y=32\\b=2\end{lgathered}

x=5

y=32

b=2

- Substitute values into x=log_{b}(y)x=log

b

(y) . Then, you obtain:

5=log_{2}(32)5=log

2

(32<em><u>)</u></em>

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Swapping rows alters the sign of the determinant:

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}

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