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Iteru [2.4K]
4 years ago
6

Choose the correct simplification of the expression (x^2y)^2 . HELLPPPP

Mathematics
1 answer:
Fynjy0 [20]4 years ago
6 0

hello

(x^2y)^2 = x^4 y^2)

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Myles is tracking the growth of his palm tree. it was 62 inches when he bought it, and it has grown 6 inches per year. what does
Gre4nikov [31]
  • The initial value represents the height of the palm tree when the tree was first bought.
  • The input for the initial value is 0.
  • The output for the initial value is 62 inches.

What is initial value?

It is given that,

The height of the palm tree at the time Myles bought it was 62 inches.

He is tracking the growth of the tree and he has observed that it has grown 6 inches per year.  

So, the initial value of the tree, here, is representing the height of the palm tree when it was bought.

As can be seen clearly, there is no input for the initial value. And, the output for the initial value is given to be 62 inches.

Learn more about initial value here:

brainly.com/question/8223651

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6 0
2 years ago
Find the weight in pounds of a 140-kilogram person. Round to the nearest hundredth. ​
Andru [333]

Answer:

308.65  lb

Step-by-step explanation:

1 lb = 0.45359 kg

140 kg * (1 lb)/(0.45359 kg) = 308.65  lb

7 0
4 years ago
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DOMAIN is the set of all input value while range is the set of all
kirza4 [7]
Range is the set of all output values of the dependent variables.
8 0
3 years ago
Which place offers a higher wage?
____ [38]

Answer:

mcdonalds

Step-by-step explanation:

6 0
3 years ago
A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from
Nimfa-mama [501]

Step-by-step explanation:

Let

m_p = mass of the painter

m_s = mass of the scaffold

m_e = mass of the equipment

T = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of m_e. The net torque on the scaffold is then

T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0

Solving for T,

9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})

or

T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]

\:\:\:\:= 423.3\:\text{N}

To solve for the the mass of the equipment m_e, use the value for T into Eqn(1):

m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}

6 0
3 years ago
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