Answer:
the equation should be corrected to fit the data of the problem. With the corrected equation a mass of 0.5 grams remains after 150 years
Step-by-step explanation:
for the mass y( in grams)
y=23* (1/2)^(t/45), t ≥ 0.
the initial mass is at t=0 , then
y= 23 grams → should be 16 grams
half-life from the equation = 45 years → should be 30 years
the correct equation should be
y=16*(1/2)^(t/30), t ≥ 0
then after 150 years → t= 150
y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams
then a mass of 0.5 grams remains after 150 years
Answer:
Step-by-step explanation:
Numerical data are majorly in digit form (i.e numbers), while a categorical data deals with grouped data. Thus some probable answers to the questions are:
1. Categorical data.
ii. Possible responses could be: English breakfast or Continental breakfast.
2. Categorical data.
ii. Possible responses could be: either by road or by air transportation
3. Numerical data.
ii. Possible responses could be: 6 or 10
4. Categorical data.
ii. Possible responses could be: snacks or soft drink
5. Numerical data.
ii. Possible responses could be: 20 minutes or 30 minutes
Answer:
64π/5 cubic units.
Step-by-step explanation:
The line x = 2 and y = x^3 intersect at the point (2 , 2^3) = (2, 8).
The required volume = volume of the cylinder with height 8 and radius 2 - the volume of shape form between the curve and the y axis when revolved about the y-axis.
Using the disk method for volumes of revolution:
Note that x = y^1/3 so:
the second volume = Integral π ((y^1/3)^2) dy between y = 0 and y = 8.
= 3/5 y^5/3 * π between 0 and 8
= 96π/5.
The required volume = π 2^2 *8 - 96π/5
= 32π - 96π/5
= 64π/5.
Word Form: Three hundred six thousands
