Let's actually find the roots, using the quadratic formula:
<span>p(x)=x^2+x+3 gives us a=1, b=1 and c=3.
-1 plus or minus sqrt(1^2-4(1)(3))
Then x = -----------------------------------------------
2
The discriminant here is negative, so the roots x will be complex:
-1 plus or minus sqrt(-11) -1 plus or minus i*sqrt(11)
x = ---------------------------------- = -------------------------------------
2 2
These are irrational roots; they cannot be expressed as the ratios of integers.</span>
Answer:
15w - 10x + 30.
Step-by-step explanation:
-5(2x - 3w - 6)
= (-5 * 2x) + (-5 * -3w) + (-5 * -6)
= -10x + 15w + 30
= 15w - 10x + 30.
Hope this helps!
It is critical to open a compass with over half the way in order for the arcs formed to meet for perpendicular bisector.
<h3>What is perpendicular bisector?</h3>
A perpendicular bisector would be a line that cuts a line segment in half and forms a 90-degree angle at the intersection point. In other words, a perpendicular bisector separates a line segment now at midpoint, forming a 90-degree angle.
Now, consider an example;
When you wish to build a perpendicular line on a line segment, like line AB, you do the following;
- Set the compass on a radius more than half the length of the line AB.
- Using A as your center, draw an arc above and below line AB.
- With the same radius and B as our center, draw additional arcs on top or below line AB to join a first arcs on the both side of the line.
- Join the two arc intersections to cut line AB at M.
A line AB appears to be bisected perpendicularly as a result. The arcs would not have met if the compass is opened less than half way down line AB.
To know more about perpendicular bisector, here
brainly.com/question/7198589
#SPJ4
