Answer:
Take the coordinates of each vertex (corner point) and subtract 2 from the x-coordinate; leave the y-coordinate alone.
Step-by-step explanation:
Example: If one vertex is the point (5, 3), then it moves left 2 units to (3, 3).
If a vertex is at (-3, 1), then it moves 2 units left to (-5, 1).
Answer:
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Step-by-step explanation:
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Multiply both by -1: 113.75-112=1.75
multiply answer by -1: -1.75